Mathematics Question and Solution
Radius of the inscribed circle, r is;
r = 2 cm.
Therefore;
Shaded Region is;
area sector with radius 2 cm and angle 120°- area triangle with two equal lengths 2 cm and the angle they form, 120° + Area quarter circle with radius 2 cm - 2(area sector with radius 2 cm and angle 60°) + Area equilateral triangle with sides 2 cm each.
= ⅓(*4π)-½(4sin120)+(¼*4π)-2((60π*4)/360)+(½*4sin60)
= ⅓(4π)-√(3)+π-⅓(4π)+√(3)
= π cm²
Or
Shaded Region is;
Quarter the area of the inscribed circle with radius 2 cm.
= ¼(2²π)
= ¼(4π)
= π cm²
