You Searched for "post"

2242 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2656240

mathematics-question-and-solution_1722172578tWgGE0.jpeg
Notice. The ascribed regular pentagon is nonagon. Its single interior angle is; ⅑*180(9-2) = 20*7 = 140° a = ½(360-(2*140)) a = ½(360-280) a = ½(80) a = 40° b = ½((180(5-2))-(3*140)) b = ½(540-420) b = ½(120) b = 60° Therefore, the required angle, alpha is; Let it be c. c = 140-a-b c = 140-40-60 c = 40° Again, c is the required angle alpha.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2656101

mathematics-question-and-solution_17221679512ZvrcY.jpeg
Sir Mike Ambrose is the author of the question. Let the single side length of the equilateral triangle be 6 unit. Therefore; Area ABC (Equilateral Triangle) is; ½(36)sin60 = 9√(3) square units. Area Orange is; Area triangle with two equal length 0.8660254038 units and angle 147.7957725°, the angle they form + Area triangle with two lengths ½√(13) units and 3 units, and angle 73.8978862497°, the angle they form. = ½*0.8660254038²sin147.7957725 + ½*½(3√(13))sin73.8978862497...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2655542

mathematics-question-and-solution_1722142704LzzeHG.jpeg
mathematics-question-and-solution_1722142811qHJzim.jpeg
Please, move right/left one time to review the solution of the question above. Thank you. Area inscribed circle is; 0.654 square units to 3 decimal places.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2655513

mathematics-question-and-solution_1722140618mixOnE.jpeg
Calculating the exact value of AC. Considering similar scalene triangles CBA and CAD. Let AC be a. 12 - a a - 27 Cross Multiply. a² = 27*12 a = √(27*12) a = √(3*3*3*2*2*3) a = 3*3*2 a = 18 cm. Again, a is AC.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2655394

mathematics-question-and-solution_1722132141cunReC.jpeg
7² = 3²+5²-2*3*5cosa 49 = 34-30cosa cosa = (34-49)/30 a = acos(-15/30 a = 120° a is angle ADC. b = 180-a b = 60° b is angle ADB. Therefore, the required angle, angle ABC is; Let it be c. c+70+60 = 180 c = 180-60-70 c = 180-130 c = 50°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2655162

mathematics-question-and-solution_1722117578kBt864.jpeg
Shaded Area exactly in square cm is; Area rectangle with length 6 cm and width 2√(3) cm - Area triangle with height (10-4√(3)) cm and base (10-4√(3))sin60. = 6*2√(3) - ½(10-4√(3))²sin60 = 12√(3) - ¼(148√(3)-240) = 12√(3) - (37√(3) - 60) = 12√(3) - 37√(3) + 60 = 60 - 25√(3) = 5(12-5√(3)) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2654980

mathematics-question-and-solution_1722108898YDOTwp.jpeg
Let the single side length of the inscribed equilateral triangle be 1 unit. Therefore; Green Area is; ¼(2√(3)+2-π) square unit. Large Semi Circle Area is; ½(π(1+(√(3)/2))² = (π(7+4√(3)))/8 square unit. Area Green ÷ Area Large Semi Circle as a single fraction in its simplest form is; ¼(2√(3)+2-π) ÷ (π(7+4√(3)))/8 = 8(2√(3)+2-π)/4(7π+4√(3)π) = (4√(3)+4-2π)/(7π+4√(3)π)

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2654351

mathematics-question-and-solution_1722083868Z2sZWM.jpeg
Calculating angle x. Let the hypotenuse of the inscribed right-angled triangle of the ascribed quadrilateral be 1 unit. 2a² = 1² a = √(1/2) units. a = 0.7071067812 units. c = (b+0.7071067812) units. Observing similar right-angled triangle side length ratios. 0.7071067812 - (b+0.7071067812) b - 0.7071067812 Cross Multiply. b²+0.7071067812b = 0.5 b²+0.7071067812b-0.5 = 0 Resolving the above quadratic equation via completing the square approach to get b. (b+0.35355...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2654008

mathematics-question-and-solution_17220693519NNjI0.jpeg
Let a be the white inscribed circle radius. a² = (0.5*8)²+b² b = √(a²-16) units. Let c be the radius of the ascribed. c² = (0.5*8+4)²+b² c² = 64+√(a²-16)² c² = 64-16+a² c = √(a²+48) units. Therefore, green inscribed area is; Area circle with radius √(a²+48) units - Area circle with radius a unit. √(a²+48)²π-a²π = a²π+48π-a²π = 48π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2653695

mathematics-question-and-solution_17220477807FS1yC.jpeg
a²+8² = 12² a = √(144-64) a = √(80) a = 4√(5) units. tanb = 8/(4√(5)) b = atan(2/√(5))° c = 90-b c = atan(√(5)/2)° cos(atan(√(5)/2)) = 4√(5)/d  d = 13.416407865 units. Therefore, area green triangle is; ½(d*12 = ½(13.416407865*12) = 80.49844719 square units.
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm