Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2733670

Notice. OE = AE = ½(6) OE = AE = 3 cm. a²+3² = 6² a² = 36-9 a = √(27) a = 3√(3) cm. tanb = a/3 b = atan(√(3)) a = 60° Shaded Area is; (0.5*3*3√(3))+(60π*6*6/360)-(0.5*6*6sin60 = ½(9√(3))+6π-9√(3) = 6π-½(9√(3)) = ½(12π-9√(3)) cm² Or (60π*6*6/360)-(0.5*3*3√(3) = 6π-½(9√(3)) = ½(12π-9√(3)) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2733657

a = (2+x) units. a is the radius of the ascribed sector. b = 2x units. x is the radius of the inscribed quarter circle. Calculating x. (2+x)² = x²+(2x)² 4+4x+x² = 5x² x²-x-1 = 0 (x-½)² = 1+(-½)² (x-½)² = (5/4) x = ½±√(5/4) x = ½±½√(5) It implies; x = ½(1+√(5)) units. x = 1.6180339887 units. Therefore, area inscribed quarter circle is; ¼(x²)π = ¼*½(1+√(5))*½(1+√(5))π = π(1+√(5))²/16 = 2.0561990865 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2733648

Calculating x. 2*2^(x)-9^(x) = 0 2*2^(x) = 9^(x) Dividing through by 2^(x). 2 = (4.5)^(x) Taking log base 10 at both sides of the equation. log2 = log(4.5)^(x) x = log2/log(4.5) x = 0.4608454206 Checking Accuracy. 2^(1+0.4608454206) + 3^(2*0.4608454206) = 0

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2731949

Area red is; ½(area square with single side length 24 units - 4(area circle with radius 6 units)) = ½(24²-4(36π)) = ½(576-144π) = 288-72π = 72(4-π) square units. Or 2(area square with side length 12 units - area circle with radius 6 units). = 2(12²-π6²) = 2(144-36π) = 72(4-π) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2731938

Sir Mike Ambrose is the author of the question. Let the single side length of the equilateral triangle be 2 unit. Therefore; Area Green is; ⅓√(3) * ⅔ = 2√(3)/9 square units. Area Yellow is; Area triangle with height (⅔) units and base 0.44905020937 units + Area triangle with two side length 0.8037975709 units and 0.6546536707 units, and angle 15.143370384°. = ½(⅔*0.44905020937) + ½(0.8037975709*0.6546536707)sin15.143370384 = 0.14968340312 + 0.06873217491 = 0.21841557803 sq...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2731933

Let the single side length of the blue area/square be x. Therefore; 5² = x² + (x+½(5-x))² 5² = x² + (½(5+x))² 25 = x² + ¼(25+10x+x²) 100 = 4x²+25+10x+x² 5x²+10x-75=0 x²+2x-15=0 (x+1)²=15+1 x = -1±√(16) x = -1±4 Therefore; x ≠ -5 x = 3 cm Therefore blue area/area square is; x² = 3² = 9 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2731257

a = 15+5 a = 20 units. a is the radius of the circle. d² = b²+c² --- (1). Where b is the width of the inscribed blue rectangle area and c is the length. 15²+20² = d² d = 25 units. d is the diagonal of the inscribed blue rectangle. Substituting d is (1) making c the subject formula. d² = b²+c² 25² = b²+c² c = √(625-b²) units. e = d+b e = (25+b) units. f = 2a f = 40 units. Calculating b. 40² = √(625-b²)²+(25+b)² 1600 = 625-b²+625+50b+b² 1600 = 1250+50b 160 =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2730809

Area red is; Area semi circle with radius 5 cm - Area sector with radius 5 cm and angle (180-2atan(2))° - Area kite with diagonal lengths √(10²+5²) cm and √(200-200cos(2atan(½))) cm + Area sector with radius 10 cm and angle 2atan(½)° - 2(area quarter circle with radius 5 cm - area triangle with height and base 5 cm respectively). = 12.5π - 11.591190225 - 50 + 46.3647608999 - 14.2699081699 = 9.77357067487 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2730778

Area red is; Area square with length 5 cm - Area quarter circle with radius 5 cm - Area sector with radius 2.5 cm and angle (180-2atan(2))° - Area kite with diagonal lengths √(5²+(2.5)²) cm and √(50-50cos(2atan(½))) cm + 2(area sector with radius 5 cm and angle 2atan(½)°) - Area triangle with two side 5 cm each, and angle 2atan(½)° + Area sector with radius 2.5 cm and angle 2atan(2)° - Area triangle with two side 2.5 cm each, and angle 2atan(2)° = 5² - ¼(5²π) - (180-2atan(2))*2.5²π÷360...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2730414

Calculating z, the diagonal of the square. 9 - 14 y - 7 Cross Multiply. Therefore; 14y = 63-9y 23y = 63 y = 63/23 units. z = √(9²+y²)+√(14²+(7-y)²) And y = 63/23 units. z = √(9²+(63/23)²)+√(14²+(7-(63/23))²) z = √(46818/529)+√(113288/529) z = (√(46818)+√(113288))/23 units. Therefore the side x of the square is; 2x² = ((√(46818)+√(113288))/23)² 2x² = (305762/529) x² = (152881/529) x² = 289 x = √(289) x = 17 units.

You Searched for "post"

2242 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Useful Tags

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "post"

2242 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?