Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2019952

Sir Mike Ambrose is the author of the question. a = 4/2tan(180/9) a = 2/tan20 units. b = 4/2tan(180/6) b = 2/tan30 units. Therefore; Red Length is; a+b = (2/tan20)+(2/tan30) = 2(tan20+tan30)/(tan20tan30) units. c = 2+b c = 2+2/tan30 c = (2tan30+2)/tan30 (a) Length Red ÷ Length Blue exactly is; (2(tan20+tan30)/(tan20tan30)) ÷ ((2tan30+2)/tan30) = 2(tan20+tan30)/2(tan20tan30+tan20) = (tan20+tan30)/tan20(tan30+1) (b) Calculating Orange Area. d = 360-140-12...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2019111

Sir Mike Ambrose is the author of the question. Let r be the radius of the three congruent circles. Calculating r. (9+r)² = (9-r)²+(9-3r)² 81+18r+r² = 81-18r+r²+81-54r+9r² 36r = 81-54r+9r² 9r²-90r+81 = 0 r²-10r+9 = 0 r ≠ 9 units. r = 1 unit. a² = (2*9²) a = 9√(2) units. b² = 2(1)² b = √(2) units. c = a-b c = 8√(2) units. (8√(2))² = 10²+2²-2*2*10cosd 128 = 104-40cosd cosd = (104-128)/40 d = 126.86989764584° (8√(2)/sin126.86989764584) = (2/sine) e = 8.13010235416° f = 180-d-e f = 45° Th...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2017172

a = 6-2 a = 4 units. b² = 6²-4² b = 2√(5) units. c = 6-b c = (6-2√(5)) units. d = asin(⅔)° tan(asin⅔) = e/(6-2√(5)) e = ⅕(12√(5)-20) units. f = 4+e f = ⅕(12√(5)) units. g² = 6²+(⅕(12√(5)))² g = ⅕(18√(5)) units. 6² = (⅕(18√(5)))²+(⅕(12√(5)))²-2*⅕*⅕*18*12*5cosh 36 = ⅕(468)-⅕(432)cosh ⅕(432)cosh = ⅕(468)-36 ⅕(432)cosh = ⅕(288) h = acos(288/432) h = 48.18968510422° i = 90-h i = 41.81031489578° Therefore; Area Shaded in square units to 2 decimal places is; ½*(6-2√(5))*⅕(12√(5)-20) + ½*6...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2017153

Let AB be 1 unit. a² = 2-2cos108 a = 1.61803398875 units. a is BE. (1.61803398875/sin156) = (b/sin6) b = 0.41582338164 units. b is BP. (1.61803398875/sin156) = (c/sin18) c = 1.22929666779 units. c is EP. d = 72-18 d = 54° e² = 1+0.41582338164-2*0.41582338164cos54 e = 0.82709091528 units. e is CP. (0.82709091528/sin54) = (1/sinf) f = 78° Notice; f is the supplementary angle of angle BPC. f' = 180-f f' = 180-78 f' = 102° f' is angle BPC. g = 72-8 g = 66° g is angle DEP. h² = 1+1.2292966...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2017107

sin60 = a/20 a = 10√(3) cm. a+b = 20 b = (20-10√(3)) cm. c = 20-2b c = 20-2(20-10√(3)) c = 20-40+20√(3) c = (20√(3)-20) cm. c = 14.64101615138 cm. Therefore; Shaded Area Red is; ½(14.64101615138)²+4((30π*20*20/360)-(½*20*20sin30)) = 107.17967697245+4(104.71975511966-100) = 107.17967697245+4*4.71975511966 = 126.05869745109 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2017071

Notice; Radius r of the circle is 6 units. Area Red is; 6(area sector with radius 6 units and angle 6°-area triangle with base 6 units and height 6sin60 units) = 6(60π*36/360 - ½*36sin60) = 6(6π-9√(3)) = 18(2π-3√(3)) square units. = 19.56659192051 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2016187

Let the the side length of the inscribed hexagon side 2 units. a² = 2-2cos120 a = √(3) units. a = 1.73205080757 units. a is the side length of the inscribed square. Therefore; Area Square is; a² = √(3)² = 3 square units. Calculating Area Purple. sin30 = b/2 b = 1 unit. c = 2b+2 c = 2*1+2 c = 4 units. sin30 = d/1 d = ½ units. e = 4-½-√(3) e = ½(7-2√(3)) units. e = 1.76794919243 units. tan18 = f/1.76794919243 f = 0.57444151456 units. g = 2f g = 1.14888302912 units. g is the side lengt...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2014794

Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicity and beauty of Mathematics to our learners, and mentor them to appreciate and love Mathematics. Communicate us to mentor/educate you Mathematics better online at affordable tuition. We are smart and clever.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2014569

Let AB be 2 units. a = atan(½)° b² = 2²+1² b = √(5) units. Let r be the radius of the inscribed circle. Calculating r. sin(atan½) = r/c c = r/sin(atan½) units. It implies; 1+r+(r/sin(atan½)) = √(5) r+(r/sin(atan½)) = √(5)-1 r+√(5)r = √(5)-1 r = (√(5)-1)/(1+√(5)) r = ½(3-√(5)) units. (a) Circle Radius ÷ AB exactly is; ½(3-√(5)) ÷ 2 = ¼(3-√(5)) (b) C Area ÷ Area Shaded is; C area is; 2² - ½*4sin(90-2atan½) - ½*4sin(2atan½) - (180-2atan2)π/360 - ½*sin(2atan2) = 4 - (6/5) - (8/5) - 0.46...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2014567

Let r be the radius of the inscribed semi circle. Calculating r. r² = (r-4)²+(r-8)² r² = r²-8r+16+r²-16r+64 r²-24r+80 = 0 It implies; r ≠ 4 cm. r = 20 cm. a² = 20²+16² a = 4√(41) cm. (4/sinb) = (4√(41)/sin45) b = 6.34019174591° c² = 2(20)² c = 20√(2) cm. Area A is; ½*4*20√(2)sin45 - ½(4²) - (6.34019174591*π*20²/360) = 40 - 8 - 22.13144423478 = 9.86855576522 cm² d = atan(20/12) d = atan(5/3)° Therefore; e = atan(⅗)° f² = 20²+12² f = 4√(34) cm. (4/sing) = (20/sin(atan⅗)) g = 5.9061...

You Searched for "post"

2242 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

We are smart and clever!

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Useful Tags

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "post"

2242 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?