Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633435

Let AB = 1 unit. a = 180-80-40 a = 60° a is angle BAD. (1/sin80) = (b/sin60) b = 0.8793852416 units. b is BD. c = 180-30-70 c = 80° c is angle BCD. (0.8793852416/sin80) = (d/sin30) d = 0.4464755882 units. d is CD. e² = 0.4464755882²+1-2*0.4464755882cos(40+70) e = 1.2266815969 units. e is AC. Therefore, the required angle, x is; (1.2266815969/sin110) = (1/sinx) x = 50°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633418

Let the side length of the ascribed square be 2 units. Area ascribed square is; 2² = 4 square units. a² = 2²+1² a = √(5) units. tanb = 2/1 b = atan(2)° c = 180-2b c = (180-2atan(2))° cos(180-2atan(2)) = d/√(5) d = 1.3416407865 units. Area Triangle Orange is; 0.5*1.3416407865√(5)sin(180-2atan(2)) = 1.2 square units. = (6/5) square units. It implies; Fraction of the square that is orange is; Area Orange ÷ Area Square = (6/5)÷4 = 6/20 = 3/10

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633401

Radius, r of the bigger inscribed red circle is; 2(1-r)²=(2r)² r²+2r-1=0 r = (√(2)-1) units. Therefore radius, x of the big inscribed green circle is; x+2(√(2)-1)=1 x = 1 - 2(√(2)-1) x = 1-2√(2)+2 x = (3-2√(2)) units. x = 0.17157287525 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633392

Sir Mike Ambrose is the author of the question. Let the single side length of the square be 2 units. Therefore; Area Square is; 2 x 2 = 4 square units. Area Blue is; Area sector with radius 1 unit and angle 63.434948823° - Area triangle with two length 1 unit and sin(atan(½)) units, and angle 63.434948823°, the angle they form. = (63.434948823π/360) - (½(sin(atan(½)))sin63.434948823) =0.5535743589 - 0.2 = 0.3535743589 = (35/99) square units. Area Blue ÷ Area Square...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633030

Sir Mike Ambrose is the author of the question. Notice; The equation of the curve is; y = (x²+32)/8 Area S will be; Area under the curve at the points on the x axis, (16/5) and 8 - Area trapezoid with two parallel length sum (6+(12/5)) unit and height (8-(16/5)) unit. = ⅓(160) - (5312/375) - (504/24) = (160000-42496-63000)/3000 = 54504/3000 = 2376/125 square unit. = 18.168 square unit.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2632929

a² = 12²+16² a = 20 units. a is BC. 12b+16b+20b = 12*16 48b = 12*16 b = 4 units. b is the radius of the inscribed circle. tanc = 12/16 c = atan(3/4)° d = 16-4 d = 12 units. e = 90-½(atan(3/4)) e = 71.5650511771° f = ½(e) f = 35.7825255885° tan35.7825255885 = g/4 g = 2.8830368802 units h = 12-g h = 9.1169631198 units. Therefore, Area DEB is; 0.5*9.1169631198²sin(atan(3/4) = 24.9357049583 square units. Or j = 2g j = 5.7660737604 units. It is;...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2632458

a = (10+x) units. a is the radius of the ascribed semi circle. sinb = 16/20 b = asin(4/5)° Calculating x. It implies; (10+x)² = 10²+21²-2*10*21cos(asin(4/5)) (10+x)² = 289 10+x = √(289) 10+x = 17 x = 17-10 x = 7 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2632111

Green Area is; Area square with length 4 units - Area quarter circle with radius 2 units - Area square with length 2 units - 3(Area square with length 1 unit) - Area square with length 3 units + Area quarter circle with radius 3 units - Area square with length 2 units + Area quarter circle with radius 2 units - Area quarter circle with radius 1 unit. = 16 - ¼(4π) - 4 - 3 - 9 + ¼(9π) - 4 + ¼(4π) - ¼(π) = 16 - 20 + ¼(9π - π) = ¼(8π) - 4 = 2π - 4 = 2(π-2) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2631801

Sir Mike Ambrose is the author of the question. Let the single side length of the large square be 2 units. Therefore; Area large square is; 2 x 2 = 4 square units. Calculating Area R. It will be; Area trapezoid of two parallel lengths (√(2)-1+2) units and height (3-√(2)) units + Area rectangle of length 2 units and width (√(2)-1) units - 2( area triangle of height (√(2)-1) units and base 1 unit) - Area sector of radius 1 unit and angle 45° - Area square of single side leng...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2631789

Let the radius of one of the small congruent circles be x. Calculating x Sin(180/7)=x/(x+1) x = xSin(180/7)+Sin(180/7) x(1-Sin(180/7))=Sin(180/7) Therefore; x = (Sin(180/7))/(1-Sin(180/7)) x = 0.76642161531 units. It implies radius of one of the congruent small circles is; 0.76642161531 units. Therefore the diameter of one of the congruent small circles is; 2*0.76642161531 = 1.53284323062 units. The length circumference of one of the small congruent circles is;...

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2138 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Useful Tags

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2138 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?