You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2138 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2636410

mathematics-question-and-solution_1721175580X9qcoB.jpeg
a = ½(360-90) a = ½(270) a = 135° It implies; b² = 1²+√(2)²-2√(2)cos135 b = √(5) units. Calculating c, radius of the quarter circle. 2c² = b² 2c² = √(5)² c = √(5/2) units. Again, c is the radius of the quarter circle. It implies, area yellow (quarter circle) is; ¼(πc²) = ¼*√(5/2)²*π = ⅛(5π) square units. = 0.625π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2636088

mathematics-question-and-solution_1721156289C5Iu2x.jpeg
Sir Mike Ambrose is the author of the question. Let the single side length of the regular nonagon be 2 units. Therefore; Area purple is; Area triangle with two equal length 2 units each and angle 140°, the angle they form + Area rectangle with length √(3) units and width 1 unit + Area rectangle with length √(8-8cos140) units and width √(3) units. = ½(4sin140)+(1*√(3))+(√(3)*√(8-8cos140)) = 9.52800747773 square units. Area yellow is; 2(area triangle with two lengths √(8-8co...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2636067

mathematics-question-and-solution_1721155345NC3ibB.jpeg
½ - 1 ½√(3) - x. Where x is the base of the blue shaded trapezium. Cross multiply ½(x) = ½(√(3)) Therefore x = √(3) units. Therefore area blue (area trapezium) is; ½*½(½√(3)+√(3)) = ¼*½(3√(3)) = (3√(3))/8 square units. = 0.64951905284 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2634868

mathematics-question-and-solution_1721090917cNyKst.jpeg
Let a be the radius of the inscribed circle. Calculating a. b = 3a units. c = b+a c = 4a units. It implies; 3a²+4a²+5a = 3a*4a 7a²+5a = 12a² 5a² = 5a a = 1 unit. Again, a is the radius of the inscribed circle. It implies; b = 3a units. And a = 1 unit. b = 3*1 b = 3 units. Therefore, the required length, x is; x = ⅓(c) And c² = 2b² c² = 2*3² c² = 18 c = √(18) c = 3√(2) units. Therefore; x = ⅓(3√(2)) x = √(2) units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2634853

mathematics-question-and-solution_1721089169yLLhjZ.jpeg
X will be; √((½*5√(2))²+(½*7)²-(½*5√(2)*½*7*2cos135) = √(½*25+¼*49-½*35√(2)cos135) = √((50+49-70√(2)cos135)/4) = ½√(99-70√(2)cos135) = ½√(169) = ½(13) = 6.5 unit

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2634844

mathematics-question-and-solution_1721088718wxflBp.jpeg
mathematics-question-and-solution_1721088780wXEyKU.jpeg
Area circle is; Let the radius of the circle be r. r²=2²+(r-1)² r²=4+r²-2r+1 r = 2.5 units. Therefore; Area circle is; π(2.5)² = 6.25π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2634311

mathematics-question-and-solution_17210583206G7EbU.jpeg
Calculating the radius of the circle. Let a be the radius of the circle. b = (27-a) units. c = (a-6) units. Therefore; a² = (a-6)²+(27-a)² a² = a²-12a+36+729-54a+a² a²-66a+765 = 0 Resolving the above quadratic equation via completing the square approach to get a, radius of the circle. (a-33)² = -765+(33)² (a-33)² = 324 a-33 = ±√(324) a = 33±18 It implies; a ≠ 33+18 a = 33-18 a = 15 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633694

mathematics-question-and-solution_1721030576RgryO4.jpeg
Let a be the radius of the circle. Therefore; a² = 2²+3² a = √(13) units. Again, a is the radius of the circle. Are circle is; πa² = π√(13)² = 13π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633613

mathematics-question-and-solution_172102568334igSk.jpeg
Notice! The ascribed triangle is equilateral. Let the two equal lengths of the composite plane shape be 1 unit each. a = 180-20-60 a = 100° (1/sin100) = (b/sin20) b = 0.3472963553 units. c² = 0.3472963553²+1-2*0.3472963553cos20 c = 0.6840402867 units. (0.6840402867/sin20) = (0.3472963553/sind) d = 10° Therefore, the required angle, x is; x+d = 60° And d = 10° x+10 = 60 x = 60-10 x = 50°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2633445

mathematics-question-and-solution_1721012218CLFm0U.jpeg
Let the blue inscribed half circle's radius be a. It implies; Calculating a. (4+a)² = a²+8² 16+8a+a² = a²+64 8a = 48 a = 6 units. Again, a is the radius of the blue inscribed half circle. b = 2a b = 12 units. b is the diameter of the blue inscribed half circle. Calculating x, length EF, Observing similar plane shape (right-angled) side length ratios. 8 - (8+x) (4+6) - (4+12+9) Cross Multiply. 8(25) = 10(8+x) 200 = 80+10x 10x = 120 x = 12 units. It implies;...
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm