Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2691646

Let a be the side length of the inscribed red equilateral triangle. It implies; (5/sin120) = (2.5/sinb) b = 25.6589062733° c = 60-b c = 34.3410937267° Calculating a. a² = 2.5²+5²-2*2.5*5cos34.3410937267 a = 3.2569390943 units. Therefore, area red inscribed equilateral triangle is; 0.5*3.2569390943²sin60 = 4.5932481676 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2690133

Sir Mike Ambrose is the author of the question. Let BC be 1 unit. Therefore; AB is 2 units. Area small square is; (⅓√(13))² = (13/9) square units. Area blue is; Area trapezium with two parallel side √(13) units and ⅓√(13) units and height ⅓√(13) units - area triangle with height ⅓√(13) units and base √(13)/6 units - area triangle with side √(13) units and 3.25764407172 units, and angle atan(1/3)° = ½(√(13)+⅓√(13))⅓√(13) - ½(⅓√(13)*√(13)/6) - ½(√(13)*3.25764407172)sin(a...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2689776

Let a be the base of the blue inscribed triangle. b = 4-1-a b = (3-a) units. c² = 2(1)² c = √(2) units. d² = 2(4)² d = 4√(2) units. e = d-c e = 3√(2) units. f² = a²+4² f = √(a²+16) units. g²+1² = (3√(2))² g² = 18-1 g = √(17) units. h = g+b h = (√(17)+(3-a)) units. Therefore, equating f and h to get a, the base of the blue inscribed triangle. √(a²+16) = (√(17)+(3-a)) a²+16 = (√(17)+(3-a))² a²+16 = ((√(17)+3)-a)² a²+16 = (7.1231056256-a)² 16 = 50.738633753...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2689761

Calculating blue inscribed half circle area. Let the radius of the blue inscribed half circle be a. 20² = 2b² b² = 200 b = √(200) b = 10√(2) units. c²+(0.5b)² = a² c² = a²-(5√(2))² c = √(a²-50) units. d = a-c d = (a-√(a²-50)) units. d is OC. Calculating a. 5√(2) - (a-√(a²-50)) 10√(2) - 5√(2) It implies; ½ = (a-√(a²-50))/(5√(2)) Cross Multiply. 2(a-√(a²-50)) = 5√(2) 2a-2√(a²-50) = 5√(2) 2a-5√(2) = 2√(a²-50) (2a-5√(2))² = 4(a²-50) 4a²-20√(2)a+50 = 4a²-2...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2689755

x = 180-2(70) x = 180-140 x = 40°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2689749

Sir Mike Ambrose is the author of the question. Area purple exactly in decimal is; Area triangle with height 5cm and base 7.5cm - Area triangle with height 3cm and base 7.5cm - Area triangle with side 2cm and 1.89765856604cm, and angle at an(3/2)° - Area triangle with side 4.26973177358cm and 4.84664832643cm, and angle (at an(⅔)-atan(2/5))° = ½(5*(15/2)) - ½(3*(15/2)) - ½(2*1.89765856604)sin(atan(3/2)) - ½(4.26973177358*4.84664832643)sin(atan(⅔)-atan(2/5)) = 7.5 - 1.57894736843 - 2.13...

Mathematics teacher and she

https://onlineedumath.com/update/mathematics-teacher-and-she/2689196

Sir Mike Ambrose is the author of the question. Notice; The single length of the square is equal the single side length of half the regular hexagon. Let it be 2 units. Therefore area square is; 2² = 4 square units. Area yellow is; Area square with length 2 units - area triangle with height 2 units and base ⅓(2√(3)) units - area triangle with height 2 units and base ⅔ units - area triangle with side (4/3) units and (4sin(atan⅓))/(3sin(120-atan⅓)) units and angle 60° = 4 -...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2687932

a = 8+10 a = 18 units. a is GK. b² = 18²-9² b = √(243) b = 9√(3) units. b is DK. tanc = 9√(3)/9 c = atan(√(3)) c = 60° d² = 9²+8²-2*8*9cos60 d = √(73) units. d = 8.5440037453 units. d is BD. (8.5440037453/sin60) = (9/sine) e = 65.8175256444° e is angle DBG. It implies; sin65.8175256444 = 9√(3)/f f = 2√(73) units. f = 17.0880074906 units. f is the diameter of the circle. g = ½(f) g = √(73) units. g = 8.5440037453 units. g is the radius of the circle. T...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2687923

Sir Mike Ambrose is the author of the question. Let the bigger regular pentagon side length be 1 unit. a = √(2-2cos180) a = 1.61803398875 units. b = sin36/sin108 b = 0.61803398875 units. c = √(2*0.61803398875²-2*0.61803398875²cos108) c = 1 unit. It implies; Area Blue is; Area triangle with height 1.61803398875 units and base sin72 units - Area triangle with height 1.61803398875 units and base 0.61803398875sin36. = ½*1.61803398875*sin72 - ½*1.61803398875*0.61803398875s...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2686853

Let the two congruent lengths be a each. 21² = a²+b²+2abcos135 441 = a²+b²+√(2)ab --- (1) 14² = a²+b²-2abcos45 196 = a²+b²-√(2)ab --- (2) Adding (1) to (2). 637 = 2a²+2b² b² = ½(637-2a²) --- (3). b = √(½(637-2a²)) --- (4). Substituting (3) and (4) in (1) to get a. 441 = a²+½(637-2a²)+√(2)a√(½(637-2a²)) 441 = a²+½(637-2a²)+a√(637-2a²) 882 = 2a²+637-2a²+2a√(637-2a²) 245 = 2a√(637-2a²) 245² = 4a²(637-2a²) 60025 = 2548a²-8a⁴ 8a⁴-2548a²+60025 = 0 It implies; a =...

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2139 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics teacher and she

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Useful Tags

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2139 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?