You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2139 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2686335

mathematics-question-and-solution_1723688770Erg1uJ.jpeg
Area orange exactly in fraction is: Area triangle with height 5√(3) cm and base 5 cm. = ½(5√(3)*5) = ½(25√(3)) cm² = 21.6506350946 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2686320

mathematics-question-and-solution_1723687714pGE8hk.jpeg
a = ½(5) a = 2.5 units. a is the radius of the inscribed half circle. tanb = 2.5/5 b = atan(1/2)° tan(atan(0.5)) = r/c ½ = r/c c = 2r units. d = 5-c d = (5-2r) units. e = (2.5-r) units. f = (2.5+r) units. Calculating r. (2.5+r)² = (5-2r)²+(2.5-r)² 6.25+5r+r² = 25-20r+4r²+6.25-5r+r² 10r = 25-20r+4r² 4r²-30r+25 = 0 (r-¼(15))² = (-¼(25))+(-¼(15))² (r-¼(15))² = (225/16)-(25/4) (r-¼(15))² = (125/16) r = ¼(15)±¼(5√(5)) It implies; r = ¼(15-5√(5)) units. r =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2684879

mathematics-question-and-solution_1723623748fbqmYc.jpeg
y = (1+x²)^(-½) Differentiating via chain rule or function of a function rule. Let u = (1+x²) du/dx = 2x Therefore; y = u^(-½) dy/du = -½u^(-3/2) And; dy/dx = (dy/du)*(du/dx) dy/dx = -½u^(-3/2)*2x u = (1+x²) It implies; dy/dx = -½(1+x²)^(-3/2)*2x dy/dx = -x(1+x²)^(-3/2) dy/dx = -x(1/√(1+x²)³) dy/dx = -x/√(1+x²)³ Or  Using quotient rule. Let u = 1 du/dx = 0 Let v = √(1+x²) = (1+x²)^½ Calculating dv/dx via chain rule or function of a function rul...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2684776

mathematics-question-and-solution_17236181157qgDyK.jpeg
a = ½(5+35) a = 20 units. a is the radius of the ascribed semi circle. b = (20-c) units. d = a-5 d = 20-5 d = 15 units. Therefore; (20-c)² = c²+15² 400-40c+c² = c²+225 175 = 40c c = 35/8 c = 4.375 units. c is the radius of the inscribed pink circle. tane = 15/(4.375) e = atan(24/7)° f = 180-e f = (180-atan(24/7))° g = ½(180-atan(24/7))° sin(½(180-atan(24/7))) = h/4.375 h = 3.5 units. It implies, the required length, x is; x = 2h x = 2*3.5 x = 7 un...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2684412

mathematics-question-and-solution_1723592767J05fgJ.jpeg
Sir Mike Ambrose is the author of the question. Let the big square area be 4 square units. Therefore the bigger square area will be; 16 square units. Area blue is; Area square with length 4 units - area triangle with height 2 units and base 1 unit - area triangle with height 4 units and base 3 units - area triangle with height (16/9) units and base ⅔ units - area triangle with height (16/9) units and base (4/3) units. = 16 - ½(2*1) - ½(4*3) - ½((16/9)*⅔) - ½((16/9)*(4/3)) = 16-...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2682636

mathematics-question-and-solution_1723508332QvMquW.jpeg
3² = a²+2² a² = 9-4 a = √(5) units. a is PQ. cosb = 2/3 b = acos(2/3)° b is angle BAC. tan(acos(2/3)) = (5√(5))/c c = 10 units. c is AB. d = 10-3 d = 7 units. d is PB. e² = 7²+(5√(5))² e² = 49+125 e = √(174) units. e is CP, diameter of the circle. f = ½(e) f = ½√(174) f is radius of the circle. Area circle is; πf² = π(½√(174))² = ¼(174)π = 43.5π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2682632

mathematics-question-and-solution_1723507982ozvMWG.jpeg
a = (x+60)° b = (180-7x)° Notice. Blue triangle is equilateral. Yellow triangle is isosceles. L1 is parallel to L2 Therefore; a = b (x+60) = (180-7x) 8x = 120 2x = 30 x = 15°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2681412

mathematics-question-and-solution_1723440840mWy7PE.jpeg
Sir Mike Ambrose is the author of the question. Area green, exactly is; Area square with length 8 cm - area trapezoid with two parallel length 8 cm and 2 cm, and height 3 cm - area trapezoid with two parallel length 7 cm and 2cm, and height 5 cm - area triangle with height 3√(5) cm and base ½(3√(5)) cm. = 64-½(30)-½(45)-¼(3√(5))² = ¼(256-195) = 61/4 = 15¼ cm² = 15.25 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2681406

mathematics-question-and-solution_1723440427DFS3pO.jpeg
Calculating area inscribed yellow rectangle. tana = 20/15 a = atan(4/3) b = 90+a b = (90+atan(4/3))° (20/sin(90+atan(4/3))) = (15/sinc) c = 26.7436839504° d = 180-(90+atan(4/3))-26.7436839504 d = 10.1262136954° (e/sin10.1262136954) = (20/sin(90+atan(4/3))) e = 5.8605710995 units. e is the width of the inscribed yellow rectangle. f = 90-26.7436839504 f = 63.2563160496° h = 180-2(63.2563160496) h = 53.4873679008° It implies; j² = 20²+20²-2*20*20cos53.487367900...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2681057

mathematics-question-and-solution_1723408064uvmaZi.jpeg
1. The Right-angled Triangle. Calculating length x. a = 9+6 a = 15 cm. a is the height of the ascribed right-angled triangle. 17 cm is the hypotenuse of the ascribed right-angled triangle. b²+15² = 17² b² = 17²-15² b² = 289-225 b = √(64) b = 8 cm. b is the base of the ascribed right-angled triangle. It implies; Calculating s. s² = 6²+8² s² = 36+64 s² = 100 s = √(100) s = 10 cm. 2. The Half Circle. Calculating A. Notice. 4 cm is the radius of the h...
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm