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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2989096

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Area yellow is; 2(area triangle with height (4.5/cos15) cm and base (4.5/cos15)sin60 cm + Area square with side (4.5/cos15) cm. = 2*½*(4.5/cos15)²(√(3)/2) + (4.5/cos15)² = (4.5/cos15)²(√(3)/2) + (4.5/cos15)² = 18.7961154131 + 21.7038845869 = 40.5 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2987380

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Let a be the side of the inscribed square. Calculating a. tan60 = a/b b = a/(tan60) cm. Where b is BS = CR. Therefore; 2b+a = 10 2a/(tan60)+a = 10 a((2/tan60)+1) = 10 a = 10(2√(3)-3) cm. a = 4.64101615138 cm. c = ½(10-a) c = 0.5(10-4.64101615138) c = 2.67949192431 cm. Where c = b. d = c+a d = 2.67949192431+4.64101615138 d = 7.32050807569 cm. Where d is BR. e = atan(4.64101615138/7.32050807569) e = 32.37365912705° It implies; Calculating TI, let it be f. tan32.37365912705 = f/g g = f/...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2985798

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Sir Mike Ambrose is the author of the question. Area green exactly in decimal is; Square side is (16/√(17)) units. Area trapezoid with parallel sides (16/√(17)) units and (4/√(17)) units, and height (16/√(17)) units - Area triangle with height (16/√(17)) units and base (4/√(17)) units - Area triangle with height (16/√(17)) units and base 3.1067961165sin(atan(13/16)) units. = ½*(16/√(17))((16/√(17))+(4/√(17))) - ½*(16/√(17))(4/√(17)) - ½*(16/√(17))*3.1067961165sin(atan(13/16)) =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2984060

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Let the bigger inscribed side of the square be 2 units. Therefore, the big inscribed square side is 1 unit. The marked angle is; ½(atan(½)+atan(2)) = ½(90°) = 45°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2982438

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Area blue is; Area square with side 10 cm - Area quarter circle with radius 10 cm - Area square with side 5 cm + Area quarter circle with radius 5 cm. = (10*10) - (¼*10*10*π) - (5*5) + (¼*5*5*π) = 100 - 25π - 25 + ¼(25π) = 75 - 25π + ¼(25π) = ¼(300 - 100π + 25π) = ¼(300-75π) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2980854

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Area pink is; 4(area semicircle with radius 4 cm - area quarter circle with radius 4√(2) cm + area triangle with height and base 4√(2) cm) respectively. It implies; 4(½(π(4²)) - ¼(π(4√(2))²) + ½(4√(2))²) = 4(8π - 8π + 16) = 4*16  = 64 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2980827

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Sir Mike Ambrose is the author of the question. Yellow area exactly in decimal cm² is; Area triangle with height 7.49903313849 cm and base 8sin(32.2356103172) cm + Area triangle with height 7.49903313849 cm and base 8sin(12.764389683) cm. = (½*7.49903313849*8sin(32.2356103172)) + (½*7.49903313849*8sin(12.764389683)) = 16 + 6.62741699809 = 22.6274169981 cm² ≈ 22.63 cm² to 2 decimal places.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2979236

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Sir Mike Ambrose is the author of the question. Let c be 4 units. Therefore; b is; 2cos(25)+2cos(25)tan(65/2) b = 2.96737905059 units. a is; 2sin(65)-2sin(65)tan(65/2) a = 0.65785209755 units. It implies; (a+b) ÷ c in decimal is; (0.65785209755+2.96737905059) ÷ 4 = 3.62523114814 ÷ 4 = 0.90630778704 ≈ 0.91 to 2 decimal places.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2977546

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Let the inscribed square side be a. tan60 = a/b a = √(3)b cm. Where b is BS = CR It implies; b+√(3)b+b = 10 (2+√(3))b = 10 b = 10(2-√(3)) cm. Therefore; a = √(3)*10(2-√(3)) a = 10(2√(3)-3) cm. a = 4.64101615138 cm. sin60 = 10(2√(3)-3)/c c = 20(2-√(3)) cm. Where c is CQ. d² = 10²+(10(2-√(3)))²-20*10(2-√(3))cos60 d = 8.96575472168 cm. Where d is AS. (8.96575472168/sin60) = (10(2-√(3))/sine) e = 15° Where e is angle PAS. f = 180-60-15 f = 105° Where f is angle BSA. g = 105-90 g = 15° Whe...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2977522

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Sir Mike Ambrose is the author of the question. Area ABC (yellow area) exactly is; Area triangle with height ⅓√(265) cm and base ((5√(26)/6)sin84.3306169587) cm. = ½*⅓√(265)*((5√(26)/6)sin84.3306169587) = 11.4722222222 cm² = 413/36 cm²
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