Mathematics Question and Solution
Notice.
Triangle ACD and Triangle BCD are right-angled triangles.
Let AD = 2 units.
AB = 6 units.
It implies;
BD = 6-2
BD = 4 units.
a² = 2(0.5*4)²
a = 2√(2) units.
a is BE = CE.
tanb = (2/4)
b = atan(½)°
b is angle DAF.
Therefore;
DF = 1 units.
Area triangle AFD is;
½(AD)*(DF)
= ½*2*1
= 1 square units.
Calculating area triangle CFE.
It implies;
Area trapezoid with parallel lengths 2 unit and 4 units respectively and height 2 units - Area trapezoid with parallel lengths 1 unit and 2 units respectively and height 2 units.
(½(4+2)*2)-(½(2+1)*2)
= 6-3
= 3 square units.
Area AFD ÷ Area CFE is;
= ⅓
