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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2304845

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Let the base of the triangle be 1 unit. a = 20+100 = 120° b = 10+10 = 20° c = 190-a-b c = 180-120-20 c = 40° It implies; (1/sin120) = (d/sin40) d = 0.742227199 units. e = 180-10-20 e = 180-30 e = 150° It implies; (0.742227199/sin150) = (f/sin20) f = 0.5077133059 units. g² = 0.5077133059²+1²-2*0.5077133059cos10 g = 0.507713306 units. Therefore, the required angle, angle x is; (0.507713306/sin10) = (0.507713306/sinx) sin10 = sinx It implies; x = 10°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2303187

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Sir Mike Ambrose is the author of the question. Radius, r of the inscribed circle is; r = (3-√(3)) cm Therefore; Area purple exactly in square cm is; Area trapezium with parallel sides (3-√(3)) cm and 4 cm, and height 3+√(3) cm - 2(area triangle with height (3-√(3)) cm and base (3√(3)-3) cm). = ½*(3+√(3))(4+3-√(3)) - 2(½*(3-√(3))*(3√(3)-3)) = (9+2√(3)) - (12√(3)-18) = (27-10√(3)) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2303172

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Shaded area is; Area trapezoid with parallel sides 58 cm and 28 cm, and height 30 cm - Area trapezoid with parallel sides 9 cm and 30 cm, and height 28 cm - Area triangle with height 12 cm and base 12 cm. = ½*30(28+58) - ½*28(9+30) - ½*12*12 = (15*86) - (14*39) - 72 = 1290 - 546 - 72 = 1290 - 618 = 672 cm²

We are smart and clever!

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2301614

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Sir Mike Ambrose is the author of the question. AB exactly is; = 16tan(3acos(8/9)) - 2√(17) = 2(8tan(3acos(8/9))-√(17)) cm = 102.760478669 cm

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2301600

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Sir Mike Ambrose is the author of the question. P(2, (16√(5)/5)) Gradient of the curve at the tangent is; = 24/5√(5) Therefore; Gradient of the curve at the normal is; = -5√(5)/24 It implies; Coordinate Q is; Q(4, (167√(5)/60)) Therefore area R as a single fraction in square units is; (Area under the curve at x = 2 and x = 4) - (Area trapezium with parallel sides 167√(5)/60 unit and 16√(5)/5 unit, and height 2 unit). = (24-⅓(8√(5))) - ½*2((167√(5)/60 )+(16√(5)/5)) =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2299150

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y = e, x = e² dy/dx at the tangent is; = 1/(y+2yIny) for y = e. dy/dx at the tangent = 1/3e Therefore; dy/dx at the normal = -3e It implies; (e-P)/(e²-0) = -3e P (height of triangle yellow) = (e+3e³) unit ((e+3e³)-0)/(0-R) = -3e R (base of triangle yellow) = ⅓(1+3e²) unit. Therefore; Area triangle yellow is; ½(⅓(1+3e²))(e+3e³) = (e+6e³+9e^(5))/6 square unit.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2299144

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Area Orange exactly in square cm is; Area trapezium with parallel sides 10 cm and 5 cm, and height 5 cm - Area triangle with height ½(5) cm and base ⅓(10) cm. = ½*10(10+5) - ½*½(5)*⅓(10) = 5(15) - (25/6) = 75 - (25/6) = 425/6 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2299126

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(AD)² = 14²+48² AD = 50 units. Notice; AD = AC It implies; CE = 14+50 CE = 64 units. It implies, CD, diameter of the semi circle is; (CD)² = 64²+48² CD = 80 units. ½(CD) = BC = BD = radius of the semi circle. BC = BD = ½(80) = 40 units. Therefore; AB is; (AB)²+40² = 54² (AB)² = 50²-40² (AB)² = 2500-1600 (AB)² = 900 AB = √(900) AB = 30 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2298926

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6² = 4²+6²-2*6*4cosa 48cosa = 52-36 cosa = 16/48 a = acos(⅓) a = 70.5287793655° b = 180-70.5287793655 b = 109.4712206345° c = 180-2(70.5287793655) c = 38.942441269° d = ½(180-70.5287793655) d = 54.7356103172° e = 180-54.7356103172-109.4712206345 e = 15.7931690483° It implies; (4/sin15.7931690483) = (f/sin54.7356103172) f = 12 cm. g = 12+6 g = 18 cm. Therefore, the required length, x is; sin38.942441269 = x/18 x = 18sin38.942441269 x = 11.313708499 cm.
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