Mathematics Question and Solution
Let BC be 1 unit.
a = 180-70-52
a = 58°
a is angle BDC.
(1/sin58) = (b/sin52)
b = 0.9292052623 units.
b is BD.
c = 189-14-54
c = 112°
c is angle BAC.
(1/sin112) = (d/sin54)
d = 0.8725529358 units.
d is AB.
e = 70+14
e = 84°
e is angle ABD.
It implies;
f² = 0.8725529358²+0.9292052623²-2*0.8725529358*0.9292052623cos84
f = 1.2063464293 units.
f is AD.
Therefore, the required angle, x is;
(1.2063464293/sin84) = (0.8725529358/sinx)
x = 46°
