You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2062 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2861830

mathematics-question-and-solution_1733307045L1sub2.jpeg
Sir Mike Ambrose is the author of the question. Let the side of the square be 2 units. Therefore; Area square is; 2² = 4 square units. Area S is; Area triangle with two side 0.98921899145 units and 1.02554900641 units, and angle 14.318078177° - Area sector with radius 2 units and angle 28.6361563539° + Area triangle with two side 2 units each, and angle 28.6361563539° = (0.5*0.98921899145*1.02554900641sin14.318078177) - (28.6361563539*2²π÷360) + (0.5*2²sin28.6361563539)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2861175

mathematics-question-and-solution_1733269947FFY8Cy.jpeg
Let the square side be 2 units. tan30 = a/2 a = ⅓(2√(3)) unit. sin60 = 2/b b = ⅓(4√(3)) units. c = 2-a c = ⅓(6-2√(3)) units. It implies; Area Shaded is; 2(½*(⅓(6-2√(3)))²sin60) + 2*⅓(6-2√(3)) = ⅓(4√(3)) square units. Area of the composite shape is; Area Shaded + 2(½*(⅓(4√(3)))²sin60) = ⅓(4√(3)) + ⅓(8√(3)) = 4√(3) square units. Therefore; Fraction Shaded is; ⅓(4√(3)) ÷ 4√(3) = ⅓

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2861163

mathematics-question-and-solution_1733268696VVPThb.jpeg
Sir Mike Ambrose is the author of the question. Shaded area coordinates are; Coordinate X is; X(½, (9/4)) Coordinate Y is; Y((-3/2), (17/4)) Coordinate Z is; Z((5/2), (33/4)) Therefore shaded area exactly in square units is; Area trapezoid with parallel side (17/4) unity and (33/4) units, and height 4 units - Area trapezoid with parallel side (17/4) units and (9/4) units, and height 2 units - Area under the curve at coordinate (½, 0) and ((5/2), 0) = ½*4((17/4)+(...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2859617

mathematics-question-and-solution_1733191506Y1cCBQ.jpeg
Let the side of the regular octagon be a. Calculating a. a² = 8 a = √(8) a = 2√(2) units. 2b² = (2√(2))² b = 2 units. c = 2√(2)+2+2 c = (2√(2)+4) units. Where c is the length of the inscribed rectangle. d = c-2(2√(2)) d = (2√(2)+4)-4√(2) d = (4-2√(2)) units. Where d is the width of the inscribed rectangle. Area Rectangle is; cd = (2√(2)+4)*(4-2√(2)) = 8 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2859583

mathematics-question-and-solution_1733189601kqzVl0.jpeg
Sir Mike Ambrose is the author of the question. Let the radius of the semi circle be 1 unit. cos20 = a/2 a = 1.87938524157 units. cos20 = 1/b b = 1.06417777248 units. c = a-b c = 0.81520746909 units. Where c is AB, the side of the square.  Area Square is; (0.81520746909)² = 0.66456321766 square units. Calculating AF. sin20 = d/2 d = 0.68404028665 units. 0.68404028665 = e 1.87938524157 = 0.81520746909 cross multiply. 1.87938524157e = 0.81520746909*0.6840402...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2858517

mathematics-question-and-solution_1733130421sZ93mP.jpeg
Sir Mike Ambrose is the author of the question. Let the side of the inscribed square be 2 units. Therefore; Area S is; Area triangle with two side 1.03528 units and 0.53589838486 units, and angle 45° = 0.5*1.03528*0.53589838486sin45 = 0.1961531464 space units. Area R is; Area triangle with two side (2√(2)-2) units and 0.65961372961 units, and angle 72.367664609° = 0.5*(2√(2)-2)*0.65961372961sin72.367664609 = 0.26038499708 space units. Area T is; Area sector with...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2858095

mathematics-question-and-solution_1733104804FqPRBw.jpeg
Sir Mike Ambrose is the author of the question. Area green total, in square unit decimal form is; Area triangle with height 6sin(atan(3/5)) units and base 6cos(atan(3/5)) units + Area triangle with height 4 units and base 4tan(atan(2/5)) units. = ½*6sin(atan(3/5))*6cos(atan(3/5)) + ½*4*4tan(atan(2/5)) = 7.94117647059 + 3.2 = 11.1411764706 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2857487

mathematics-question-and-solution_1733067541pyr12i.jpeg
3^(x) - √(3)^(x)*√(3)^(6) = -162 3^(x) - 3^(x/2)*3^(3) = -162 Let p be 3^(x) p - 27p^(½) + 162 = 0 p-18p^(½)-9p^(½)p+162 = 0 p^(½)(p^(½)-18)-9(p^(½)-18) = 0 (p^(½)-18) = 0 or (p^(½)-9) = 0 p = 324 or p = 81 And p is 3^(x) It implies; 3^(x) = 324 or 3^(x) = 81 x = log(324)/log(3) or x = 4 Therefore; x = log(324)/log(3) or x = 4 x = 5.26185950714 or x = 4

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2857013

mathematics-question-and-solution_1733042405xP5e4g.jpeg
Let 1 unit be AB = AC. a = 12+24 a = 36° a is angle ABC = angle ACB. b = 180-2(a) b = 180-72 b = 108° b is angle BAC. c = b-6 c = 108-6 c = 102° c is angle CAD. d = 180-12-6 d = 162° d is angle ADB. It implies; (1/sin162) = (e/sin12) e = 0.6728163648 units. e is AD. f² = 0.6728163648²+1²-2*0.6728163648*1cos102 f = 1.3162274259 units. f is CD. Therefore, the required angle, x is; (1.3162274259/sin102) = (0.6728163648/sinx) x = 30° x is angle ACD.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2856718

mathematics-question-and-solution_1733021721XZvXcR.jpeg
Notice; Hexagon Area = 24√(3) square units. Calculating hexagon side length. Let it be a. (6a²)/(4tan30) = 24√(3) ½(3√(3))a² = 24√(3) 3a² = 48 a = 4 units. Equation of the curve is; y = ½(x²) ------ (1). sin60 = b/4 b = 2√(3) units. cos60 = c/4 c = 2 units. Gradient = ((4√(3)+2)-(2√(3)+2))/(2-4) Gradient = -√(3) (y-(4√(3)+2))/(x-2) = -√(3) y = -√(3)x+6√(3)+2 ---- (2). Equation (1) and (2). ½(x)² = -√(3)x+6√(3)+2 x = 3.53906 y = ½(3.53906)² y = 6...
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm