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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2552194

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a = (4-x) units. It implies; 4² = (4-x)²+2² 12 = 16-8x+x² x²-8x+4 = 0 (x-4)² = -4+(-4)² (x-4)² = -4+16 (x-4)² = 12 x = 4±√(12) x = 4±2√(3) It implies; x = (4-2√(3)) units. a = (4-x) And x = (4-2√(3)) units. a = 4-(4-2√(3)) a = 2√(3) units. b = 2+a b = (2+2√(3)) units. b is the radius of the big green quarter circle. c = b-4 c = (2+2√(3))-4 c = (2√(3)-2) units. c is the radius of the small green quarter circle. It implies, area green is; ¼*π(2+2√(3))²+¼*π(2√...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2548180

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Notice! The side length of the inscribed biggest square is 5 units. Calculating inscribed red area. tana = 2.5/5 a = atan(½)° b = 2atan(½)° tanc = 5/2.5 c = atan(2)° d = 2atan(2)° Therefore, area red is; Area sector with radius 2.5 units and angle 2atan(2) - Area triangle with height 2.5 units and base 2.5sin(2atan(2)) units + Area sector with radius 5 units and angle 2atan(½) - Area triangle with height 5 units and base 5sin(2atan(½)) units - 2(area quarter circle wit...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2546616

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a² = 24²+7² a = 25 units. a is AC. b = 7+a b = 32 units. c² = b²+24² c = √(32²+24²) c = 40 units. c is the diameter of twice the quarter circle (semi circle (2AB)). d = ½(c) d = 20 units. d is AB, radius of the quarter circle. It implies, length BC is; (BC)²+20² = 25² BC = √(625-400) BC = √(225) BC = 15 units.

We are smart and clever!

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2530322

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Let a be the radius of the quarter circle. b = (a-10) units. b is the width of the inscribed rectangle. c = (a-5) units. c is the length of the inscribed rectangle. Therefore; a² = (a-5)²+(a-10)² a² = a²-10a+25+a²-20a+100 a²-30a+125 = 0 Resolving the above quadratic equation via factorization approach to get a, radius of the quarter circle. a²-25a-5a+125 = 0 a(a-25)-5(a-25) = 0 (a-5)(a-25) = 0 It implies; a ≠ 5 a = 25 units. Therefore; b = (a-10) units. And...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2528115

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Notice! The composite plane shape consist of two congruent quarter circles with radius 2 units each. a = 3-2 a = 1 unit. cosb = 1/2 b = acos(½)° b = 60° Area green is; 2(area sector with radius 2 units and angle 60° - area triangle with height 2 units and base 2sin(60) units). = 2((60π*2*2÷360)-(0.5*2*2sin(60))) = 2(⅔(π)-√(3)) = ⅔(2π-3√(3)) square units. Perimeter red is; 2(length of arc with radius 2 units and angle 60°) = 2(60π*2*2÷360) = ⅔(2π) units. Therefore...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2522568

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Green area will be; ½(area quarter circle with radius (2+√(2)) unit) - area isosceles right-angled triangle with height and base √(2) unit respectively - area sector with radius √(2) unit and angle 135° = ½(¼(2+√(2))²π) - (½(√(2))²) - (π(√(2))²x135÷360) = ¼(3+2√(2))π - 1 - ¾(π) = ¼(3π+2√(2)π-4-3π) = ¼(2√(2)π-4) = ½(√(2)π-2) square unit.

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2505977

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Our amazing learners back in the day, 2013 From left to right; Alamin, Esther, Favour, Victoria, Mufida and Amina. We are proud of you all.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2495869

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tana = 1/2 a = atan(1/2)° b = 180-2a b = (180-2atan(½))° Notice! Radius of the inscribed circle is 1 unit. Area yellow is; Area triangle with height 2 units and base 1 unit - Area square with side 1 unit + Area quarter circle with radius 1 unit - Area sector with radius 1 unit and angle (180-2atan(½))° + Area triangle with height 1 unit and base (180-2atan(½)) units. = (½*2*1)-(1*1)+(0.25π*1*1)-((180-2atan(½))π*1*1/360)+(0.5*1*1sin(180-2atan(½))) = 1-1+0.7853981634-1.107148...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2490228

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Let R be radius of the quarter circle. Let r be radius of the inscribed circle. R will be; √(3²+4²) R=√(25) R= 5 unit. Calculating r, radius of the inscribed circle. Therefore r will be; (5-r)²=(3+r)²+r² 25-10r+r²=9+6r+r²+r² r²+16r-16=0 Therefore resolving the quadratic equation via completing the square side to get r, radius of the inscribed circle. (r+8)² = 16+8² (r+8)² = 80 r = -8±√(80) r = -8±4√(5) It implies; r ≠ -8-4√(5) r = -8+4√(5) r = 4(√(5)-2) units....
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