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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2440596

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Let the radius of the ascribed quarter circle be a. It implies; a² = 5²+b² b = √(a²-25) units. 6² = b²+c² c² = 36-b² c = √(36-√(a²-25)²) c = √(36-(a²-25)) c = √(61-a²) units. d = 5+c d = (5+√(61-a²)) units. Calculating a. (5+√(61-a²))² = a²+6² 25+10√(61-a²)+61-a² = a²+36 10√(61-a²)-a² = a²+36-86 100(61-a²) = (2a²-50)² 100(61-a²) = 4a⁴-200a²+2500 6100-100a² = 4a⁴-200a²+2500 4a⁴-100a²-3600 = 0 a⁴-25a²-900 = 0 Let a² = p. p²-25p-900 = 0 Resolving the above quadratic equation via completing...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2436205

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(4+5+3)² = 2a² a² = 72 a = 6√(2) cm. a is the congruent adjacent sides of the right-angled triangle. b² = √(72)²+3²-2*√(72)*3cos45 b² = 81-36 b = √(45) b = 3√(5) cm. (3√(5)/sin45) = (3/sinc) c = 18.4349488229° d² = √(72)²+4²-2*√(72)*4cos45 d² = 88-48 d = √(40) d = 2√(10) cm. (2√(10)/sin45) = (4/sine) e = 26.5650511771° f = 90-c-e f = 90-18.4349488229-26.5650511771 f = 45° 2g² = 5² g² = 25/2 g = √(25/2) g = ½(5√(2)) cm. g = 3.5355339059 cm. It implies; Shaded Area is; Area quarter circl...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2419797

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2410245

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2403409

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Let the length and width of the ascribed rectangle be 3 units and 2 units respectively. Calculating red area. It is; Area quarter circle with radius 2 units - Area sector with radius 1.5 units and angle 2atan(2/1.5)° + Area triangle with height 1.5 units and base 1.5sin(2atan(2/1.5)) units - Area sector with radius 2 units and angle 2atan(1.5/2)° + Area triangle with height 2 units and base 2sin(2atan(1.5/2)) units + Area semi with radius 1 unit - Area sector with radius 1 unit and angle 2ata...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2398853

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Calculating area red. tana = 3/5 a = atan(3/5)° b = 2a b = 2atan(3/5)° tanc = 5/3 c = atan(5/3)° d = 2c d = 2atan(5/3)° Therefore, red area is; 2(area circle with radius 5 units) - 4(area quarter circle with radius 5 units and angle 2atan(3/5)° - area triangle with height 5 units and base 5sin(2atan(3/5)) units) - 4(area quarter circle with radius 3 units and angle 2atan(5/3)° - area triangle with height 3 units and base 3sin(2atan(5/3)) units) = 2(5²π)-4(2atan(3/5)π*5²/360 - (0.5*5*5si...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2398027

we-are-smart-and-clever_1709808345eoQc0F.jpeg
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2391371

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Shaded Area is; 4(area quarter circle with radius 2 units - area triangle with height and base 2 units each) + 2(area square with side 2 √(2) units - area semi circle with radius 2 units) = 4(¼*4π-½*4)+2((2√(2))²-½*4π) = 4π-8+16-4π = -8+16  = 8 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2390478

mathematics-question-and-solution_1709449067eD9i4V.jpeg
Calculating Area Blue Plus Area Orange. Radius of the congruent four semi circles is 1 unit each. (a-1)²+1² = 2² a²-2a+2 = 4 a²-2a-2 = 0 Resolving the above quadratic equation via completing the square approach to get a. (a-1)² = 2+(-1)² a-1 = ±√(3) a = 1±√(3) It implies; a ≠ 1-√(3) a = 1+√(3) units. a = 2.7320508076 units. a is the side length of the square. Area Blue Plus Area Orange is; Area square with side (1+√(3)) units - 4(area semi circle with radius 1 unit) = (1+√(3))²-4(0.5π*1...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2389414

we-are-smart-and-clever_1709394730vd5Tdu.jpeg
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!
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