Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
26th May, 2024

a² = 24²+7²

a = 25 units.

a is AC.


b = 7+a

b = 32 units.


c² = b²+24²

c = √(32²+24²)

c = 40 units.

c is the diameter of twice the quarter circle (semi circle (2AB)).


d = ½(c)

d = 20 units.

d is AB, radius of the quarter circle.


It implies, length BC is;


(BC)²+20² = 25²

BC = √(625-400)

BC = √(225)

BC = 15 units.

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