Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2263785

Let the side of the regular pentagon be 1 unit. Notice; The regular pentagon side is equal the regular heptagon side. a = ⅐(180*5) a = ⅐(900)°, the single interior angle of the regular heptagon. b = 2a b = ⅐(450)° tan(⅐(450)) = c/0.5 c = 1.03826069829 units. cos(⅐(450)) = 0.5/d d = 1.15238243548 units. Where d is the radius of the ascribed circle. e = 180-⅐(900) e = ⅐(360)° tan18 = 0.5/f f = 1.53884176859 units. g² = 1.15238243548²-0.5² g = 1.03826069828 units. h = f-g h = 0.5005810...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2260176

Let a be the diameter of the semi circle. a² = b²+14² b² = a²-196 b = √(a²-196) It implies; b² = 6²+6²-2*6*6(-cosc) a²-196 = 72+72cosc a²-196-72 = 72cosc 72cosc = a²-268 cosc = (a²-268)/72 --- (1). cosc = 14/a --- (2). Equating (1) and (2). cosc = cosc (a²-268)/72 = 14/a a³-268a = 1008 a³-268a-1008 = 0 Resolving the polynomial equation. a = 18 units. It implies; Radius, r of the semi circle is; ½(a) = ½(18) = 9 units.

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Please, browse through the link below. Screenshot slide video of our teaching and learning activities with our super smart and amazingly, very clever learners. It is in memory of Late Sound Sultan (Legendary Advocate Musician). Rest on, Sound Sultan. https://www.facebook.com/100085657676431/posts/pfbid0sABrt5eAC5KgmzRhTc37TRVcb8LUWugQU2zjuwnBQdJc32AudxpytFQ1F7Uti6k3l/?app=fbl

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255511

Area blue is; Area square with side 10 cm - Area triangle with height 5 cm and base 10 cm - Area triangle with height 10 cm and base (4.71404520791sin45) cm - Area triangle with height 5 cm and base (4.71404520791sin45) cm - Area triangle with height 5 cm and base (2.2360679775sin(atan(2))) cm = 10² - ½(10*5) -½(10*4.71404520791sin45) - ½(5*4.71404520791sin45) - ½(5*2.2360679775sin(atan(2))) = 100 - 25 - ⅓(50) - ⅓(25) - 5 = 70 - ⅓(50) - ⅓(25) = ⅓(210-75) = ⅓(135) cm² = 45 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255445

Calculating r, radius of the Semi Circle. ½(π)r² = 338π r² = 676 r = 26 cm. a = ½(48) a = 24 cm. Calculating x. It implies; Observing Pythagoras Rule. 26² = 24²+x² x² = 676-576 x² = 100 x = 10 cm.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255255

a² = 6²+8² a = √(100) a = 10 cm. a is the hypotenuse of the ascribed right-angled triangle. Let b be the hypotenuse of the blue inscribed right -angled triangle. It implies, observing similar triangles ratio. 6 = 3 10 = b, cross multiply. 6b = 3*10 b = 5 cm. Let c be the base of the inscribed blue right-angled triangle. Calculating c. 5² = 3²+c² c = √(25-9) c = √(16) c = 4 cm. Therefore, Area Blue is; ½*3*c = ½*3*4 = 6 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2179361

Let the red square side be 1 unit. Area Red is; 1² = 1 square units. Calculating Area Blue. (1/sin30) = (a/sin126) a = 1.6180339887 units. a = 2sin126 units. It implies; Area Blue is; 0.5*2sin126sin24 = sin24sin126 square units. Therefore; Area Blue ÷ Area Red exactly is; sin24sin126÷1 = sin24sin126 = 0.3290568565 exactly in decimal. Calculate Alpha to 1 decimal place. b = 180-100 b = 80° c = 126-80 c = 46° (1/sin30) = (d/sin24) d = 0.8134732862 units. (0.8134732862/sin30) = (e/si...

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Please, browse through the link below to review short video of our teaching and learning activities. Thank you. Video 98. Class with Oghosa (year 8) 28/09/2023 https://www.facebook.com/100085657676431/posts/pfbid0fyDrECA4adicnzDU2pbNmddUZY4GNoo9rTrpLV1kMcHesTn1Y5F45yDX6trpT3QPl/?app=fbl

Short Video of Our Teaching and Learning Activities

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Please, browse through the link below to review short video of our teaching and learning activities. Thank you. Video 103. Class with Derick and Zino (year 7 and year 6 respectively) 03/10/2023 https://www.facebook.com/100085657676431/posts/pfbid0s2Q2ihgbv8C4nrU1T4DivkEJmVAaA8D4ytyWNDNTzypuTnaFdMTrmB4be23iRQ2Jl/?app=fbl

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2144034

Sir Mike Ambrose is the author of the question. Let the side length of the square be 10 unit. Area square is; 10² = 100 square unit. Therefore; Area R is; Area semi circle with radius 5 unit - Area sector with radius 5 unit and angle (180-2atan(2))° - Area kite with diagonal lengths √(10²+5²) unit and √(200-200cos(2atan(½))) unit + Area sector with radius 10 unit and angle 2atan(½)° - 2(area quarter circle with radius 5 unit - area triangle with height and base 5 unit respectively) - area s...

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Mathematics Question and Solution

Mathematics Question and Solution

We are smart and clever!

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Short Video of Our Teaching and Learning Activities

Short Video of Our Teaching and Learning Activities

Mathematics Question and Solution

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