Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2372555

Area blue is; Area square with side 10 cm - Area quarter circle with radius 10 cm - Area square with side 5 cm + Area quarter circle with radius 5 cm. = (10*10) - (¼*10*10*π) - (5*5) + (¼*5*5*π) = 100 - 25π - 25 + ¼(25π) = 75 - 25π + ¼(25π) = ¼(300 - 100π + 25π) = ¼(300-75π) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2370512

a² = (2r)²+r² a² = 5r² a = √(5)r units. a is BD. Where r is the radius of the circle. b = ½(a) b = ½(√(5)r) units because BD, points B and D are symmetry with respect to length AC. tanc = 2r/r c = atan(2)° c is angle DBF. d = 90-c d = (90-atan(2))° tane = 2/1 e = atan(2)° e is angle BAC. tanf = 1/2 f = atan(½)° f is angle ACB. Notice! c (angle DBF) + f (angle ACB) = 90° Or atan(2) + atan(½) = 90° It implies; (½(BD))BC is a right-angled triangle. Notice! ½(BD) = ½(√(5)r) units. Calcula...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2354558

a² = 10²+10²-2*10*10cos150 a = 19.31851652578 cm. Where a is AF which is equal AE. (19.31851652578/sin150) = (10/sinb) b = 15° Where b is angle BAF. tan15 = c/10 c = 2.67949192431 cm. It implies; Area Green Region is; Area square with side 10 cm - 2(area triangle with height 2.67949192431 cm and base 10 cm. = 10² - ½*2(10*2.67949192431) = 100-26.7949192431 = 73.2050807569 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2331178

Let the three equal lengths be 1 unit. it implies; AB = BD = DE = 1 unit. a² = 1²+1²-2*1*1cos100 a = 1.5320888862 units a is AD. c = ½(180-100) c = 40° c is angle ADB. d = 180-40-40 d = 100° d is angle ADE. e² = 1.5320888862²+1²-2*1*1.53cos100 e = 1.969615506 units. e is AE. It implies; (1.969615506/sin100) = (1/sinf) f = 30° f is angle DAE. g = 40+30 g = 70° g is angle BAE Therefore, the required angle x (angle ACB) is; x+70+100 = 180 x = 180-170...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2320358

a = 180-50-30 a = 100° a is angle AED. Let DE = 1 unit. (1/sin30) = (b/sin100) b = 1.969615506 units. b is AD. c = 180-80-50 c = 50° c is angle CAD. (1.969615506/sin80) = (d/sin50) d = 1.5320888862 units. d is CD. CE = 1.5320888862-1 CE = 0.5320888862 units. e = 180-50 e = 130° e is angle ADB. f² = 0.5320888862²+1.969615506²-2*1.969615506*0.5320888862cos130 f = 2.3472963553 units. f is AB. Therefore, calculating the required angle, angle BAD (angle x). (2.3472963553/sin130) = (1.96961...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2312970

Area of coloured region is; Area triangle with height 53.3479501083 m and base 60sin(102.042575143) m + Area triangle with height 100.027406452 m and base √(5924)sin(12.5245961777) m = (½*53.3479501083*60sin(102.042575143)) + (½*100.027406452*√(5924)sin(12.5245961777)) = 1565.21739131 + 834.782608691 = 2400 m²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2312121

Let the two equal red lengths of the triangle, ABC be 1 unit. Therefore; AB = CE = 1 unit. a = 180-100-20 a = 60° (b/sin100) = (1/sin20) b = 2.8793852416 units. b is BC. c = 2.8793852416-1 c = 1.8793852416 units. c is BE. Notice; BE = CD = the blue equal lengths. It implies; d² = 1+1.8793852416²-2*1*1.8793852416cos20 d = 1 unit. d is DE. Notice; CE = DE = 1 unit. Therefore; e = 180-2(20) e = 180-40 e = 140° e is angle CED. It implies; The required angle, x is; x+140 = 180 x = 180-14...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2304845

Let the base of the triangle be 1 unit. a = 20+100 = 120° b = 10+10 = 20° c = 190-a-b c = 180-120-20 c = 40° It implies; (1/sin120) = (d/sin40) d = 0.742227199 units. e = 180-10-20 e = 180-30 e = 150° It implies; (0.742227199/sin150) = (f/sin20) f = 0.5077133059 units. g² = 0.5077133059²+1²-2*0.5077133059cos10 g = 0.507713306 units. Therefore, the required angle, angle x is; (0.507713306/sin10) = (0.507713306/sinx) sin10 = sinx It implies; x = 10°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2282072

Let the equal lengths be 1 unit. (1/sin20) = ((1+y)/sin120) 1+y = (sin120/sin20) y = (sin120/sin20)-1 y = 1.5320888862 units. z² = 1+1.5320888862²-2*1.5320888862cos40 z = 1 unit. It implies, the required angle x is; 120-(180-2(40)) = x x = 120-(180-80) x = 120-100 x = 20°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2281996

The equation of the curve is; 0-32=-a(8-4)² -32 = -16a a = 2 Therefore; y-32 = -2(x-4)² y = -2(x²-8x+16) +32 y = -2x²+16x-32+32 y = 16x - 2x² It implies; (Area (2197/24)+ Area triangle with height b unit and base a unit + Area under the curve at x = 8 and x = a) = Area under the curve at x = 8 and x = 0 2197+12ab-192a²+16a³=0 ----------- (1) Notice; b = 16a-2a² --------- (2) Substitute (2) in (1). Therefore; a = ½(13) unit And b = ½(39) unit It implies; Area shaded/Area orange in it...

You Searched for "100"

289 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Facebook Page

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "100"

289 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?