Calculating angle x.
Let 2 units be the side length of the ascribed square and also the radius of the inscribed red quarter circle.
Notice.
BM = CM, meaning point M horizontal shares the both vertical side lengths, OA and BD of the ascribed square to equal halves.
a = ½(2)
a = 1 unit.
a is half the vertical side length, OA and BD of the ascribed square.
sinb = ½
b = 30°
b is angle BOM.
c = ½(180-b)
c = ½(180-30)
c = ½(150)
c = 75°
c is angle OBM.
It implies, angle x (angle BCD) is;
Notice again, angle x (angle BCD) alternates angle OBM (angle OBC).
Meaning x (angle BCD) is equal angle OBC).
Therefore;
x = 75°
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