Mathematics Question and Solution
Calculating Theta.
Let it be x.
Notice.
ABCD is a square.
Let 1 unit be CP = DQ.
It implies;
a = 180-33-48
a = 99°
(b/sin99) = (1/sin33)
b = 1.81347328615 units.
b is the side length of the square.
c = b-1
c = 1.81347328615-1
c = 0.81347328615 units.
c is CQ.
d = 90-48
d = 42°
d is angle PCQ.
e² = 1²+0.81347328615²-2*0.81347328615cos42
e = 0.6728163648 units.
Therefore x, angle theta is;
(0.81347328615/sinx) = (0.6728163648/sin42)
sinx = (0.81347328615sin42)/0.6728163648
x = asin(0.80901699437)
x = 54°
Again, x is angle theta.
