Mathematics Question and Solution
Calculating Area BCDA, Area of the Square.
Let x be the side length of the square.
½*a*x = 9
ax = 18
a = (18/x) units.
a is CP.
b = x-a
b = x-(18/x)
b = (x²-18)/x units.
Notice.
c = 25-9
c = 16 square units.
c is area BPQ.
And triangle ABQ is equal triangle DPQ.
It implies;
Area BCDA, x² is;
x² ~ 25
((x²-18)/x)² ~ 16
x ~ 5
(x²-18)/x ~ 4
Cross Multiply.
4x = 5(x²-18)/x
Cross Multiply Again.
4x² = 5(x²-18)
4x² = 5x²-90
5x²-4x² = 90
x² = 90 square units.
Again, x² is area BCDA, area of the square.
