Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
16th July, 2026

Calculating Alpha.


Let it be x.


Let a be the radius of the ascribed quarter circle.


b = (a-√(2)) units.


c = (a-2√(2)) units.


Calculating a.


a ~ (a-√(2))

(a-2√(2)) ~ √(2)


 Cross Multiply.


√(2)a = a²-2√(2)a-√(2)a+4


√(2)a = a²-3√(2)a+4


a²-4√(2)a+4 = 0


(a-2√(2))² = -4+(-2√(2))²


(a-2√(2))² = -4+8


(a-2√(2))² = 4


a-2√(2) = ±2


a = 2√(2)±2


It implies;


a ≠ 2√(2)-2 units.


a = 2√(2)+2 units.

Again, a is the radius of the ascribed quarter circle.


d = a-2√(2)

d = 2√(2)+2-2√(2)

d = 2 units.


It implies;


Calculating theta, angle x.


sinx = 2/(2√(2)+2)


x = asin(2/(2√(2)+2))


x = 24.4698005207°


Calculating green area.


e = 90-x

e = 90-24.4698005207

e = 65.5301994793°

 

Therefore, area green is;


½*2*(2√(2)+2)sin65.5301994793


= (2√(2)+2)sin65.5301994793


= 4.39473645387 square units.


Or


f²+2² = (2√(2)+2)²

f² = 8+8√(2)+4-4

f = √(8+8√(2)) units.


Green Area is;


½*2*√(8+8√(2))


= √(8+8√(2)) square units.


= 4.39473645387 square units.

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