Mathematics Question and Solution
Calculating x, the required red length.
a = (16-y) cm.
y is the radius of the inscribed blue circle.
b = ½(16)
b = 8 cm.
Calculating y.
(16-y)² = y²+8²
256-32y+y² = y²+64
256-32y = 64
192 = 32y
y = 6 cm.
Again, y is the radius of the blue inscribed circle.
tanc = 8/6
c = atan(4/3)°
d = 2c
d = 2atan(4/3)°
Therefore, x, the required red length is;
x² = 6²+6²-2*6*6cos(2atan(4/3))
x² = 92.16
x = √(92.16)
x = 9.6 cm.
