Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
8th June, 2026

Calculating x/y.


Let 10 units be the side length of the ascribed square.


x+y = 10 

y = (10-x) --- (1).


Let a be each of the 2 equal angles.


tana = x/(10-x) --- (2).


tan(2a) = 10/(10-x)


2tana/(1-tan²a) = 10/(10-x)


10-10tan²a = 20tana-2xtana --- (3).


Substituting (2) in (3).


10-10(x/(10-x))² = 20(x/(10-x))-2x(x/(10-x))


10(10-x)²-10x² = 20x(10-x)-2x²(10-x)


10(100-20x+x²)-10x² = 200x-20x²-20x²+2x³


1000-200x = 200x-40x²+2x³


2x³-40x²+400x-1000 = 0


x³-20x²+200x-500 = 0


It implies;


x = 3.104


And x+y = 10


y = 10-x

y = 10-3.104

y = 6.896


Therefore, x/y is;


3.104/6.896


= 3104/6896


= 194/431


= 0.45011600928

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