Calculating length AB.
a² = 6²+4²-2*4*6cos60
a² = 52-24
a = √(28) units.
a = 2√(7) units.
a is BD.
(√(28)/sin60) = (4/sinb)
b = 40.8933946491°
b is angle CBD.
c = 60-b
c = 19.1066053509°
c is angle ABD.
d = 180-150-c
d = 10.8933946491°
d is angle ADB.
Therefore, the required length, AB is, let it be e.
(e/sin10.8933946491) = (√(28)/sin150)
e = 2 units.
Again, e is length AB.
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