Calculating length FB.
Notice.
Triangle BCF is equilateral.
It Implies;
Let FB = CB = FC = x.
(17/sin60) = (15/sina)
sina = (15sin60)/17
a = 49.8305486955°
a is angle BFD.
b = 180-60-a
b = 70.1694513045°
Therefore, x, length FB is;
(x/sin70.1694513045) = (17/sin60)
x = (17sin70.1694513045)/sin60
x = 18.4658560997 units.
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