Mathematics Question and Solution
Calculating area of the circle.
Let x be the radius of the circle.
Method 1.
It implies;
2*(4+2) = 6*a
6a = 12
a = 2 units.
b = 6+2
b = 8 units.
It implies, a cyclic regular quadrilateral (rectangle) is inscribed the circle with length 8 units and width 4 units.
c² = 8²+4²
c = √(64+16)
c = √(80)
c = 4√(5) units.
c is the diameter of the circle.
x = ½(c)
x = ½(4√(5))
x = 2√(5) units.
Again, x is the radius of the circle.
Area circle is;
πx²
= π(2√(5))²
= 20π square units.
Method 2.
x² = (½*4)²+(½*8)²
x² = 4+16
x² = 20
x = √(20)
x = 2√(5) units.
Again, x is the radius of the circle.
Area circle is;
πx²
= 20π square units.
