Calculating x, the required angle.
a = ⅛*180(8-2)
a = ⅛*180*6
a = ½*45*6
a = 135°
a is the single interior angle of the regular octagon.
b = ⅕*180(5-2)
b = ⅕*180*3
b = 36*3
b = 108°
b is the single interior angle of the regular pentagon.
c = ½(a)
c = ½(135)
c = 67.5°
d = 360-2b-c
d = 360-2(108)-67.5
d = 360-216-67.5
d = 76.5°
Therefore x, the required angle is;
x = 180-d
x = 180-76.5
x = 103.5°
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