Calculating the required area.
Let it be y.
a = x cm²
b = (50-x) cm²
c = 60-b
c = 60-(50-x)
c = (10+x) cm²
d = 40-c
d = 40-(10+x)
d = (30-x) cm²
It implies;
y = d+x
y = (30-x)+x
y = 30 cm²
Again, y is the required area.
Or
40+50 = 60+y
y = 90-60
y = 30 cm²
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