Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
22nd July, 2025

Calculating Yellow Area.


Let a be the side length of the square.


b = ½(a) units.


c² = a²+(½(a))²

c² = ¼(5a²)

c = ½√(5)a units.

c is the radius of the half circle.


It implies;


a ~ ½√(5)a

d ~ a

Cross Multiply.

½√(5)d = a

d = 2a/√(5)

d = ⅕(2√(5)a) units.


e = ½(d)

e = ⅕√(5)a units.


f = c-e

f = ½√(5)a-⅕√(5)a

f = ⅒(3√(5))a units.


Calculating a.


½*a*½(a)+½*⅒(3√(5))a*⅕(2√(5)a) = 15

¼(a²)+⅒(3a²) = 15

5a²+6a² = 300

11a² = 300

a = 10√(3)/√(11)

a = 10√(33)/11 units.


g = 2f

g = 2*⅒(3√(5))a

g = ⅕(3√(5))a units 


a² = (10√(33)/11)²

= (100*33)/(11*11)

= 300/11 square units.

a² is the area of the square.


h = d*g

h = ⅕(2√(5)a)*⅕(3√(5))a

h = ⅕(6a²)

And a² = 300/11 square units.

h = ⅕*6*(300/11)

h = (360/11) square units.

h is the area of the inscribed rectangle.


Area yellow is;


a²-15+h-15


= ((300/11)-15)+((360/11)-15)


= (660/11)-30


= 60-30


= 30 square units.

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