Mathematics Question and Solution
Sir Mike Ambrose is the author of the question.
Let length AB be 3 units.
Therefore;
AC = 20 units.
It implies;
Area large square is;
20²
= 40 square units.
Area orange is;
Area triangle with two side 17 units and 32.0319709782 units, and angle (180-atan(10/7))° + Area triangle with two side 20 units and 44.0408623507 units, and angle 53.4269678346° - Area square with side 20 units + Area triangle with height 3 units and base 4.2857142857 units.
= (0.5*32.0319709782*17sin(180-atan(10/7))) + (0.5*44.0408623507*20sin53.4269678346) - 20² + (0.5*4.2857142857*3)
= 223.053711371 + 353.69129172 - 400 + 6.42857142855
= 183.17357452 space units.
Therefore;
Area Orange ÷ Area Large Square, exactly in decimal is;
183.17357452 ÷ 400
= 0.4579339363
