Mathematics Question and Solution
Let a be the radius of the half circle.
b = (3-a) units.
It implies, calculate a.
a² = 2²+b²
a² = 4+(3-a)²
a² = 4+9-6a+a²
6a = 13
a = (13/6) units.
Again, a is the radius of the half circle.
Therefore, the required area is;
Area half circle with radius (13/6) units - Area triangle with height 2 units and base 3 units.
= ½(13/6)²π-½(2*3)
= ½(π(169/36)-6)
= (169π-216)/72 square units.
= 4.3740160897 square units.
