6² = a²+(2+3)²
a² = 36-25
a = √(11) units.
b² = 3²+c²
b = √(9+c²) units.
b is the diameter of the circle.
d = c-a
d = (c-√(11)) units.
e² = 2²+(c-√(11))²
e = √(4+c²-2c√(11)+11)
e = √(c²-2c√(11)+15) units.
Therefore;
√(9+c²)² = 6²+√(c²-2c√(11)+15)²
9+c² = 36+c²-2c√(11)+15
2√(11)c = 51-9
2√(11)c = 42
√(11)c = 21
c = (21√(11))/11 units.
c = 6.3317382361 units.
Notice!
PQ = e = √(c²-2c√(11)+15)
PQ = √((6.3317382361)²-2(6.3317382361)√(11)+15)
PQ = 3.6181361349
Or
d = (c-√(11))
And c = 6.3317382361 units.
d = 6.3317382361-√(11)
d = 3.0151134457 units.
It implies, length PQ is;
(PQ)² = 2²+3.0151134457²
PQ = √(13.0909090904)
PQ = 3.6181361349 units.
We appreciate you contacting us. Our support will get back in touch with you soon!
Have a great day!
Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support