Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
10th June, 2024

Calculating x.


7² = x²+5²+2*5*xcosa

49 = x²+25+10xcosa

24 = x²+10xcosa

10xcosa = 24-x²

cosa = (24-x²)/(10x) --- (1).


b = (x+5) units.


7² = x²+(x+5)²-2x(x+5)cosa

49 = x²+x²+10x+25-(2x²+10x)cosa 

24 = 2x²+10x-(2x²+10x)cosa --- (2).


Substituting (1) in (2).


24 = 2x²+10x-(2x²+10x)cosa

And cosa = (24-x²)/(10x)

24 = 2x²+10x-(2x²+10x)(24-x²)/(10x)

240= 20x²+100x-(2x+10)(24-x²)

240 = 20x²+100x-(48x-2x³+240-10x²)

240 = 20x²+100x-48x+2x³-240+10x²

480 = 2x²+30x²+52x

x³+15x²+26x-240= 0


It implies;


x = 3 units.

x is the required side length.

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