Mathematics Question and Solution
Notice!
The inscribed blue area is a square.
Let the inscribed blue area side length be a.
Calculating a.
tan63 = a/b
b = a/tan63 --- (1).
tan43 = a/c
c = a/tan43 --- (2).
It implies;
(2)+a+(1) = 10
(a/tan43)+a+(a/tan63) = 10
1.07236871a+a+0.5095254495a = 10
2.5818941595a = 10
a = 3.8731254584 cm.
Again, a is the side length of the inscribed blue square (square).
Therefore, area blue is;
a²
= 3.8731254584²
= 15 cm²
