Let the radius of the inscribed circle be x.
a = (3-x) units.
b = 7-3
b = 4 units.
c = (7-x) units.
d = a+c
d = (3-x)+(7-x)
d = (10-2x) units.
Therefore, x (radius of the inscribed circle) is;
(2x)²+b² = d²
(2x)²+4² = (10-2x)²
4x²+16= 100-40x+4x²
16 = 100-40x
40x = 100-16
40x = 84
10x = 21
x = 2.1 units.
Again, x is the radius of the inscribed circle.
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