Mathematics Question and Solution
Let the base of the ascribed triangle be 1 unit.
a = 180-20-20-10-10
a = 120°
(1/sin120) = (b/sin20)
b = 0.3949308436 units.
c = 180-120-20
c = 40°
(0.3949308436/sin40) = (d/sin120)
d = 0.5320888862 units.
e = 180-40-60
e = 80°
(0.3949308436/sin80) = (f/sin60)
f = 0.3472963553 units.
g² = 0.3472963553²+0.5320888862²-2*0.3472963553*0.5320888862cos20
g = 0.2375646984 units.
(0.2375646984/sin20) = (0.5320888862/sinh)
h = 50°
j = 180-h
j = 180-50
j = 130°
Therefore the required angle x, is;
x+j = 180
x+130 = 180
x = 180-130
x = 50°
