Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
24th March, 2024

Let the two congruent blue semi circle's radius be a.


1 = πb²

b² = 1/π

b = √(1/π) units.

b is the radius of the yellow circle.


tanc = a/2a

c = atan(½)°


d = 2c

d = 2atan(½)°


sin(atan(½)).= √(1/π)/e

e = 1.261566261 units.


f = e+b

f = 1.261566261+√(1/π)

f = 1.8257558445 units.


It implies 


(a+1.8257558445)² = (2a)²+a²


a²+3.651511689a+3.3333844037 = 5a²

4a²-3.651511689a-3.3333844037 = 0


Resolving the above quadratic equation.


a = 1.47707 units.

Again, a is the radius of the two congruent blue semi circle


Notice, the two blue congruent semi circles with equal radius will make a circle.


It implies;

Area Blue (a circle) is;

πr²

= π(1.47707)²

= 6.8541251139 square units.

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