Mathematics Question and Solution
Sir Mike Ambrose is the author of the question.
P coordinate is;
P(3, 9)
Q coordinate is;
Q(2, 5), Q(3, 5)
It implies;
Shaded area exactly in its square units simplest form is;
(Area under the curve at x = 2 and x = 3) - (Area trapezoid with parallel sides ⅓(23) units and 9 units, and height 1 unit).
= (8+ln(81/16)) - ½((23/3)+9)
= (8+ln(81/16))-½(50/3)
= (8+ln(81/16))-⅓(25)
= (ln(81/16)-⅓) square units.
= 1.2885270991 square units.
