Mathematics Question and Solution
Notice!
Radius of the circle, r is;
r = √(50)
r = 5√(2) units.
a² = 2²+6²
a² = 4+36
a = √(40)
a = 2√(10) units.
tanb = 6/2
b = atan(3)°
c = ½(a)
c = ½(2√(10))
c = √(10) units.
cosd = c/r
cosd = √(10)/(5√(2))
d = acos(⅕√(5))°
e = b-d
e = (atan(3)-acos(⅕√(5)))°
Therefore, the required length, x is;
x² = 2²+(5√(2))²-2*2*5√(2)cos(atan(3)-acos(⅕√(5)))
x = 5.0990195136 units.
x = 5.1 units to 2 decimal places.
