Mathematics Question and Solution
3A = ¼(9*9)π
Where;
3A is the sum of the inscribed three equal areas.
¼(9*9)π is the area of the ascribed quarter circle.
It implies;
12A = 9*9π
A = (27/4)π cm²
A is an area of the three equal areas that are inscribed the quarter circle.
Notice.
r, radius of the quarter circle is 9 cm.
Poo9
Calculating x.
a = (9-x) cm.
a is the radius of the inscribed quarter circle.
It implies;
¼(9-x)²π = (27/4)π
(9-x)² = 27
9-x = 3√(3)
9-3√(3) = x
x = 3(3-√(3)) units.
x = 3.8038475773 units.
