Mathematics Question and Solution
Sir Mike Ambrose is the author of the question.
Let the side of the regular quadrilateral (square) be 4 units.
Area square is;
4²
= 16 square units.
Area Red is;
Area triangle with height 4.56295238924 units and base 3.14062240575sin46.50530982298 - Area triangle with height 1.46815433032 units and base 3.14062240575sin46.50530982298
= 5.19860210712 - 1.6724847454
= 3.52611736172 square units.
It implies;
Area Red ÷ Area Square to 2 decimal places is;
3.52611736172 ÷ 16
= 0.22038233511
≈ 0.22
