Mathematics Question and Solution
Using 12 cm as AB.
Circle's radius, r = 6√(2) cm.
a = 45-atan(½)
a = 18.43494882292°
sin(atan(0.5)) = 6/b
b = 13.416407865 cm.
cos18.43494882292 = c/6√(2)
c = 8.049844719 cm.
d = 2*8.049844719
d = 16.099689438 cm.
e = 16.099689438-13.416407865
e = 2.683281573 cm.
f = 2*2.683281573
f = 5.366563146 cm.
g = 180-atan2
g = 116.56505117708°
h² = 5.366563146²+6²-12*5.366563146cos116.56505117708
h = 9.67470929796 cm.
h = CG.
(9.67470929796/sin116.56505117708) = (6/sinj)
j = 33.69006752598°
k = 180-33.69006752598-116.56505117708
k = 29.74488129694°
k = Angle MCG.
l = 29.74488129694+45
l = 74.74488129694°
m = 0.5(180-74.74488129694)
m = 30.51023740612°
(n/sin30.51023740612) = (6√(2)/sin74.74488129694)
n = CF.
n = 4.46525044521 cm.
o = 9.67470929796-4.46525044521
o = 5.20945885275 cm.
o = FG.
It implies;
Length EF is;
(EF)² = 5.20945885275²+2.683281573²-2*2.683281573*5.20945885275cos33.69006752598
EF = 3.32820117735 cm.
