Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
4th July, 2023

a² = 6²+8²-2*6*8cos30

a = 4.10628314132 cm.

a = DE.


(4.10628314132/sin30) = (8/sinb)

b = 103.06431342951°

b = Angle ADE.


Angle AED = 180-30-103.06431342951 

= 46.93568657049°


tan30 = c/6

c = 3.46410161514 cm.

c = CH.


d = 8-2*3.46410161514 

d = 1.07179676972 cm.


e = 1.07179676972+3.46410161514

e = 4.53589838486 cm.


f = atan(6/4.53589838486) 

f = 52.91133691903°


g = 90-52.91133691903 

g = 37.08866308097°


h = 37.08866308097-30

h = 7.08866308097°


i = 60+46.93568657049

i = 106.93568657049°


j = 180-106.93568657049-7.08866308097

j = 65.97565034854°


(8/sin65.97565034854) = (k/sin7.08866308097)

k = 1.0808744285 cm.

k = EF.


cos30 = 6/l

l = 6.92820323028 cm.

l = BH


m = 8-6.92820323028

m = 1.07179676972 cm.

m = EH 


n² = 1.07179676972²+1.0808744285²-2*1.0808744285*1.07179676972cos106.93568657049

n = 1.72972903458 cm.

n = FH.


(1.72972903458/sin106.93568657049) = (1.0808744285/sino)

o = 36.71114966331°


p = 180- 36.71114966331-60

= 83.28885033669°

p = Angle EGH.


(1.07179676972/sin83.28885033669) = (q/sin60)

q = 0.9346072274 cm.

q = GH.


FG = FH-GH

FG = 1.72972903458-0.9346072274

FG = 0.79512180718 cm.


It implies;


FG ÷ GH is;

0.79512180718÷0.9346072274 

= 0.85075503791

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