Notice;
Angle DCE = -(Angle BCG)
Let Angle DCE be x.
Calculating K.
4k² = 4k²+k²-4k*kcosx
cosx = (¼) --- (1).
144 = 4k²+k²-2k²(-cosx)
144 = 5k²-2k²(-cosx)
Substituting (1) in (2).
144 = 5k²-2k²(-¼)
144 = 6k²
k² = 24
k = 2√(6) units.
It implies;
2k is 4√(6) units.
Total square areas is;
(4√(6))²+(2√(6))²
= 16*6+4*6
= 6(16+4)
= 6(20)
= 120 square units.
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