Mathematics Question and Solution
Let CE be 2 units.
Let the square side be a.
b =√(2)a unit.
c = (√(2)a-2) units.
Calculating a
2²+2² = (√(2)a-2)²
8 = 2a²-4√(2)a+4
2a²-4√(2)a-4 = 0
a²-2√(2)a-2 = 0
(a-√(2))² = 2+2
a = √(2)±2
Therefore;
a ≠ (√(2)-2) units.
a = (√(2)+2) units.
a is AD.
tand = (2/(√(2)+2))
d = atan(2/(√(2)+2))°
d = 30.36119340482°
d is angle ABF.
(BG)² = 1+3.41421356237²-2*1*3.41421356237cos45
BG = 2.79793265193 units.
(2.79793265193/sin45) = (1/sine)
e = 14.63880659519°
e is angle CBG.
Calculating required angle x.
x = 90-angle(ABF)-angle(CBG)
x = 90-30.36119340482-14.63880659519
x = 90-45
x = 45°
