Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
25th June, 2023

AD = √(40²-20²)

AD = 20√(3) units.


AE = DE = ½(AD)

= 10√(3) units.


Angle BED is;

= atan(20/(10√(3)))

= atan(⅔√(3))°

= 49.10660535087°


Angle DAC is;

= 30°


(EF)² = 300+625-20√(3)*25cos30

EF = 5√(7) units.


(5√(7)/sin30) = (25/sina)

a = 70.89339464913°

a is angle DEF.


Therefore required angle is;


Angle BED + Angle DEF

= 49.10660535087+70.89339464913

= 120°

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