Mathematics Question and Solution
EG = DG = ½√(12²+6²)
EG = DG = 3√(5) cm.
Ang CDE = atan(½)
It's implies;
(CG)² = 45+144-2*36√(5)cos(atan(½))
CG = 3√(5) cm.
CG = 6.7082039325 cm.
tan(atan(½)) = a/6
a = 3 cm.
b = 12-3
b = 9 cm.
Angle BAG = atan(9/6)
Angle BAG = atan(3/2)°
sin(atan(3/2)) = 9/(AG)
AG = 9/sin(atan(3/2))
AG = 3√(13) cm.
Therefore;
AF = AG-FG
AF = 3√(13)-3√(5)
AF = 3(√(13)-√(5)) cm.
AF = 4.10844989389 cm.
AF ÷ CG is;
3(√(13)-√(5))÷3√(5)
= (√(13)-√(5))/√(5)
= ⅕(√(65)-5)
= 0.61245154966
Or
AF ÷ CG is;
4.10844989389÷6.7082039325
= 0.61245154966
