Mathematics Question and Solution
a² = 6²+12²
a = 6√(5) cm.
Where a is CE = EF.
b² = 2(a²)
b² = 2(6√(5))²
b² = 360
b = 6√(10) cm.
Where b is CF.
Angle DCE = atan(½)°
Angle ECF = 45°
Angle FCM = 90-45-atan(½)
Angle FCM = 18.43494882292°
tan18.43494882292 = c/12
c = 4 cm.
Angle AEF = 90-atan2
Angle AEF = atan(½)°
(AF)² = 36+180-2*6*6√(5)cos(atan(½))
AF = 6√(2) cm.
(6/sind) = (6√(2)/sin(atan(0.5)))
d = 18.43494882292°
Where d is angle AFE.
Angle CFM = 180-45-18.43494882292
Angle CGM = 116.56505117708°
Angle CMF = 180-116.56505117708-18.43494882292
Angle CMF = 45°
It implies;
BM = 12 cm.
