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Mathematics Question and Solution.

https://onlineedumath.com/update/mathematics-question-and-solution/2840743

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Sir Mike Ambrose is the author of the question. Let AB be 2 unit. Therefore CD = 1 unit. It implies; Area Blue is; Area triangle with height 0.72111025509 unit and base sin(atan(3/2)) unit. = 0.5*0.72111025509sin(atan(3/2)) = 3/10 space unit. Area Green is; Area trapezoid with two parallel side (3/2) unit and 1 unit, and height ½ unit - Area triangle with height (3/2) unit and base ½ unit. = ½*½((3/2)+1) - ½*½(3/2) = (5/8) - (3/8) = ¼ space unit. Area Red is; Area...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2829677

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Sir Mike Ambrose is the author of the question. Let the side of the regular pentagon be 1 unit. Therefore; Area purple is; Area trapezium with two parallel side 0.07294901687 units and 0.38196601125 units, and height cos18 units. = 0.5*cos18*(0.07294901687+0.38196601125) = 0.21632495093 space units. Area yellow is; Area trapezium with two parallel side 0.27345747199 units and 1 unit, and height 1 unit - Area triangle with height 0.27345747199 units and base 0.198678483 uni...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2812734

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Sir Mike Ambrose is the author of the question. Calculating the equation of the curve. y-b=a(x-4)² ----- (1) At coordinate (8, 0) -b=16a Therefore; a = -b/16 Sub. a in (1) to get the equation of the curve. y-b= (-b/16)(x-4)² It implies; y = (-bx²/16)+(bx/2) ----- (2) Calculating b. The area of the curve at point (8, 0) = 1280/27 It implies; (-32b/3)+16b=1280/27 b = 1280/(16*9) b = 80/9 Therefore sub. b in (2). y = (-(80/9)x²/16)+((80/9)x/2) y...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2804990

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Sir Mike Ambrose is the author of the question. Let length AB be 3 units. Therefore; AC = 20 units. It implies; Area large square is; 20² = 40 square units. Area orange is; Area triangle with two side 17 units and 32.0319709782 units, and angle (180-atan(10/7))° + Area triangle with two side 20 units and 44.0408623507 units, and angle 53.4269678346° - Area square with side 20 units + Area triangle with height 3 units and base 4.2857142857 units. = (0.5*32.0319709782...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2803507

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Sir Mike Ambrose is the author of the question. Let the side of the square be 2 units. Therefore; Area square is; 2² = 4 square units. Area S is; Area triangle with two side 0.98921899145 units and 1.02554900641 units, and angle 14.318078177° - Area sector with radius 2 units and angle 28.6361563539° + Area triangle with two side 2 units each, and angle 28.6361563539° = (0.5*0.98921899145*1.02554900641sin14.318078177) - (28.6361563539*2²π÷360) + (0.5*2²sin28.6361563539)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2802130

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Sir Mike Ambrose is the author of the question. Let the side of the inscribed square be 2 units. Therefore; Area S is; Area triangle with two side 1.03528 units and 0.53589838486 units, and angle 45° = 0.5*1.03528*0.53589838486sin45 = 0.1961531464 space units. Area R is; Area triangle with two side (2√(2)-2) units and 0.65961372961 units, and angle 72.367664609° = 0.5*(2√(2)-2)*0.65961372961sin72.367664609 = 0.26038499708 space units. Area T is; Area sector with radi...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2795785

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Sir Mike Ambrose is the author of the question. Let the side of the square be 2 units. Area square is; 2² = 4 square units. Area orange is; Area triangle with two side 0.70710678119 units and 1.2928932188 units, and angle (90+asin(⅓))° + Area triangle with two side 1.66764761969 units and 1.20710678117 units, and angle 66.436529825° = 0.5*0.70710678119*1.2928932188sin(90+asn(⅓)) + 0.5*1.66764761969*1.20710678117sin(66.436529825) = 0.43096440627 + 0.9225889843 = 1.3535533905...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2792503

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Sir Mike Ambrose is the author of the question. Let the ascribed quarter circle radius be 4 units. Therefore; Area blue is; Area triangle with two side 1 unit and 3 units, and angle 2asin(1/3)° = ½*3sin(2asin(1/3)) = 0.94280904158 space units. Area red is; Area triangle with two side 1 unit and 3 units, and angle (180-2asin(1/3))° + Area triangle with two side 2 units and √(44/3) units, and angle 100.02498786° = ½*3sin(180-2asin(1/3)) + ½*2*√(44/3)sin100.02498786 = 0.942809...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2779739

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Sir Mike Ambrose is the author of the question. Let the radius of the semi circle be 1 unit. Therefore; Area lilac is; Area triangle with height 0.26794919243 units and base 1 unit = ½(0.26794919243) = 0.13397459622 space units. Area large square is; Area square with side length 1 unit = 1² = 1 square unit. Area Lilac ÷ Area Large Square in its simplest decimal form is; 0.13397459622 ÷ 1 = 0.13397459622 ≈ 0.134 to 3 decimal places.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2778284

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Sir Mike Ambrose is the author of the question. Let the single side length of the regular octagon be 2 units. Therefore;  Area green is; Area triangle with height and base √(2) units + Area triangle with height 2√(2) units and base 1 unit - Area triangle with height √(2) units and base ½ units. = ½(√(2))² + ½(2√(2)) - ½(½*√(2)) = 1 + √(2) - ¼√(2) = ¼(4+4√(2)-√(2)) = ¼(4+3√(2)) space units. Area blue is; Area square with side 2 units + Area rectangle with length 2 units an...
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